NTA NEET Registration 2026 Live Updates: UG Application Form & Exam Date Soon

Enthalpy of Neutralization of Strong Acid and Strong Base MCQ - Practice Questions with Answers

Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET

Syllabus

Quick Facts

4 Questions around this concept.

Solve by difficulty

MEDIUM

The absolute enthalpy of neutralization of the reaction:

$MgO_{\left ( s \right )}+2HCl_{\left ( aq \right )}\rightarrow MgCl_{2\left ( aq\right )}+ H_{2}O\left ( l \right ) will\, \, be:$

-57.33 kJ $mol^{-1}$

Greater than -57.33 kJ $mol^{-1}$

Less than -57.33 kJ $mol^{-1}$

57.33 kJ $mol^{-1}$

View Solution

Concepts Covered - 1

Enthalpy Of Neutralisation

Heat of Neutralization

It is enthalpy change during neutralization of 1 equivalent of an acid and base.

Case of Strong Acid and Strong Base:

$\mathrm{HCl + NaOH \longrightarrow NaCl + H_2O}$

The enthalpy change of the above reaction is equal to -13.7 kcal eq^-1 or -57.3 kJ eq^-1.

It is to be noted that the enthalpy of neutralisation of 1 equivalent of any strong acid or stong base is equal to -13.7 kcal eq^-1 or -57.3 kJ eq^-1.

$\mathrm{H^+ + OH^- \longrightarrow H_2O, \Delta H = -13.7\ kcal\ mol^-}$

Case in which any one of the Acid or Base (or Both) are weak:

In case one of the acid or base is weak, then some part of the heat will be used up for ionisation of the weak component and the heat liberated will be lesser than the above values

For example

$\mathrm{CH_3COOH + NaOH \longrightarrow CH_3COONa + H_2O, |\Delta H| < 13.7\ kcal\ eq^-}$

Properties of enthalpy of neutralisation:

It is always exothermic $\mathrm{\Delta H = - ve }$
The heat of neutralization of strong acid and strong base is always 13.7 Kcal/mole or 57 kJ/mole.
It is independent of nature of strong acid or strong base.
If one electrolyte is weak then $\mathrm{\Delta H }$ will be less than —13.7 Kcal as some amount of heat will be absorbed in ionization of weak electrolyte.
In case of HF, $\mathrm{\Delta H }$ is more due to more hydration of F^- ions.