Moment Of Inertia Of Hollow Cylinder MCQ - Practice Questions with Answers

Let I= Moment of inertia of the hollow cylinder about its axis passing through its C.O.M

To calculate I

Consider a cylinder of mass M, radius R and length L as shown in figure

Now take an elemental ring of radius R and mass dm which is coaxial to hollow cylinder.

And Moment of inertia of elemental ring about axis of cylinder and ring is $d I=d m R^2$
So integrating Moment of inertia of such elemental rings will give I

$$
\mathrm{So}_{\mathrm{s}} \mathrm{I}=\int d I=\int d m R^2=M R^2
$$