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Motion of connected blocks over pulley is considered one the most difficult concept.
20 Questions around this concept.
A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 ( vertically) . If the acceleration of the system is g/8, then the ratio of the masses is
Two masses m1 = 5kg and m2 = 4.8 kg tied to a string are hanging over a light frictionless pulley. What is the acceleration (in m/s2 ) of the masses when lifted free to move?
( g = 9.8 m/s2 )
Calculate the acceleration of the system as shown in the figure, assume all the surfaces are smooth
NEET 2025: Syllabus | Most Scoring concepts | NEET PYQ's (2015-24)
The system shown is released at rest. Speed of block A (in m/s), after B has descended by 2 cm is
When one block is hanging, the other is on the Table as shown in the below figure.
For this case what is the formula of tension force between them?
Equation of mation for $m_1$
$$
F_{n e t}=T-m_1 g=m_1 a
$$
Equation of Motion for $m_2$
$$
\begin{aligned}
& F_{\text {net }}=m_2 g-T=m_2 a \\
& a=\frac{\left[m_2-m_1\right] g}{m_1+m_2} \\
& T=\frac{2 m_1 m_2 g}{m_1+m_2}
\end{aligned}
$$
When one Block is hanging, the other is on the Table
$$
a=\frac{m_2 g}{m_1+m_2}
$$
$$
T=\frac{m_1 m_2 g}{m_1+m_2}
$$
Three blocks, two are hanging and one is at the rest on the smooth horizontal table
$$
\begin{aligned}
& m_1 a=m_1 g-T_1 \\
& m_2 a=T_2-m_2 g \\
& T_1-T_2=M a
\end{aligned}
$$
$$
a=\frac{\left(m_1-m_2\right) g}{m_1+m_2+M}
$$
$$
T_1=\frac{m_1\left(2 m_2+M\right) g}{\left(m_1+m_2+M\right)}
$$
$$
T_2=\frac{m_2\left(2 m_1+M\right) g}{\left(m_1+m_2+M\right)}
$$
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