Sticking Of Person With The Wall Of Rotor MCQ - Practice Questions with Answers
Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET
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9 Questions around this concept.
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EASYA person of mass 80 pounds was made to stand at the centre of the rotor. Then the rotor was made to rotate at . Then the bottom floor was removed. What happened to the person before the removal of the floor and after the floor removal?
Directions: If "K" means "subtracted from", "L" means "divided by", "M" means "added to" and "D" means "multiplied by", then 96 L 4 K 6 M 11 D 9 = ?
Concepts Covered - 1
Sticking of Person with the wall of Rotor(Death well)
F = weight of person (mg)
$
\begin{aligned}
& \mu R=m g \\
& \mu F_c=m g \\
& \mu m \omega_{\min }^2 r=m g \\
& \therefore \omega_{\min }=\sqrt{\frac{g}{\mu r}}
\end{aligned}
$
Where $F=$ friction force
$
\mathrm{F}_{\mathrm{C}}=\text { centrifugal force }
$
$
\omega_{\min }=\text { minimum angular velacity }
$
$
\mu=\text { coefficient of friction }
$
r = radius of Rotor
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