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Sticking Of Person With The Wall Of Rotor MCQ - Practice Questions with Answers
Edited By admin | Updated on Sep 25, 2023 25:23 PM | #NEET
Quick Facts
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9 Questions around this concept.
Solve by difficulty
EASYA person of mass 80 pounds was made to stand at the centre of the rotor. Then the rotor was made to rotate at . Then the bottom floor was removed. What happened to the person before the removal of the floor and after the floor removal?
Directions: If "K" means "subtracted from", "L" means "divided by", "M" means "added to" and "D" means "multiplied by", then 96 L 4 K 6 M 11 D 9 = ?
Concepts Covered - 1
Sticking of Person with the wall of Rotor(Death well)
F = weight of person (mg)
$
\begin{aligned}
& \mu R=m g \\
& \mu F_c=m g \\
& \mu m \omega_{\min }^2 r=m g \\
& \therefore \omega_{\min }=\sqrt{\frac{g}{\mu r}}
\end{aligned}
$
Where $F=$ friction force
$
\mathrm{F}_{\mathrm{C}}=\text { centrifugal force }
$
$
\omega_{\min }=\text { minimum angular velacity }
$
$
\mu=\text { coefficient of friction }
$
r = radius of Rotor
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