Moment Of Inertia Of A Ring MCQ - Practice Questions with Answers

Let I=Moment of inertia of a RING about an axis through its center and perpendicular to its plane

To find out I Consider a ring of mass M, radius R, and center O.

Take an elementary portion of the ring of mass dm and length dx. 

$\mathrm{So}_{,} d I=d m \cdot R^2$
And, $I=\int d I=\int d m * R^2=R^2 \int d m=M R^2$