NEET Physics Most Asked Numericals To Score 120+ Marks
Ques: 1
A wire of resistance $R$ is cut into 8 equal pieces. From these pieces, two equivalent resistances are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is (NEET 2025)
Option 1) $\frac{R}{8}$
Option 2) $\frac{R}{64}$
Option 3) $\frac{R}{32}$
Option 4) $\frac{R}{16}$
Chapter: Current Electricity
Correct Answer: Option 4
Explanation:
The wire is cut into 8 equal pieces, so each piece has resistance
$R_{piece}=\frac{R}{8}$
The resistance of each group is
$\frac{1}{R_{group}}=\frac{1}{R/8}+\frac{1}{R/8}+\frac{1}{R/8}+\frac{1}{R/8}=\frac{32}{R}$
$R_{group}=\frac{R}{32}$
Since the groups are connected in series, the net resistance is
$R_{net}=\frac{R}{32}+\frac{R}{32}=\frac{R}{16}$
Hence, the answer is option (4).
Ques: 2
In a potentiometer circuit, a cell of EMF 1.5 V gives a balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occur? (NEET 2021)
Option 1) 60 cm
Option 2) 21.6 cm
Option 3) 64 cm
Option 4) 62 cm
Chapter: Current Electricity
Correct Answer: Option 1
Explanation:
$\frac{E_1}{E_2}=\frac{l_1}{l_2}$
$\frac{1.5}{2.5}=\frac{36}{l_2}$
$l_2=60cm$
Hence, the answer is option (1).
Ques: 3
An electric dipole with dipole moment $5\times10^{-6}Cm$ is aligned with the direction of a uniform electric field of magnitude $4\times10^5NC^{-1}$. The dipole is then rotated through an angle of $60^\circ$ with respect to the electric field. The change in the potential energy of the dipole is (NEET 2025)
Option 1) 1.5 J
Option 2) 0.8 J
Option 3) 1.0 J
Option 4) 1.2 J
Chapter: Electrostatic Potential and Capacitance
Correct Answer: Option 3
Explanation:
Given,
$p=5\times10^{-6}Cm$
$E=4\times10^5NC^{-1}$
$\theta_i=0^\circ,\ \theta_f=60^\circ$
$\Delta U=U_f-U_i$
$\Delta U=pE(\cos\theta_i-\cos\theta_f)$
$\Delta U=5\times10^{-6}\times4\times10^5\times(1-\frac{1}{2})=1J$
Hence, the answer is option (3).
Ques: 4
The radius of the Martian orbit around the Sun is about 4 times the radius of the orbit of Mercury. The Martian year is 687 Earth days. Then, which of the following is the length of 1 year on Mercury? (NEET 2025)
Option 1) 124 earth days
Option 2) 88 earth days
Option 3) 225 earth days
Option 4) 172 earth days
Chapter: Gravitation
Correct Answer: Option 2
Explanation:
From Kepler’s third law, $T^2\propto R^3$
$\frac{T_{Mercury}}{T_{Mars}}=\left(\frac{R_{Mercury}}{R_{Mars}}\right)^{3/2}=\left(\frac{1}{4}\right)^{3/2}=\frac{1}{8}$
$T_{Mercury}=\frac{687}{8}\approx88days$
Hence, the answer is option (2).
Ques: 5
The minimum energy required to launch a satellite of mass $m$ from the surface of the earth of mass $M$ and radius $R$ in a circular orbit at an altitude of $2R$ from the surface of the earth is: (NEET 2024)
Option 1) $\frac{5GMm}{6R}$
Option 2) $\frac{2GMm}{3R}$
Option 3) $\frac{GMm}{2R}$
Option 4) $\frac{GMm}{R}$
Chapter: Gravitation
Correct Answer: Option 2
Explanation:
Using energy conservation,
$U_i+K_i=U_f+K_f$
$-\frac{GMm}{R}+K_i=-\frac{GMm}{3R}+\frac{1}{2}m\frac{GM}{3R}$
$K_i=\frac{5GMm}{6R}$
Hence, the answer is option (2).
Ques: 6
A body of mass 60 g experiences a gravitational force 3.0 N when placed at a particular point. The magnitude of the gravitational field intensity at that point is: (NEET 2022)
Option 1) 50 N/kg
Option 2) 20 N/kg
Option 3) 180 N/kg
Option 4) 0.05 N/kg
Chapter: Gravitation
Correct Answer: Option 1
Explanation:
Gravitational field intensity
$g=\frac{F}{m}=\frac{3}{60\times10^{-3}}=50Nkg^{-1}$
Hence, the answer is option (1).
Ques: 7
In a certain camera, a combination of four similar thin convex lenses is arranged axially in contact. Then the power of the combination and the total magnification in comparison to the power $(p)$ and magnification $(m)$ for each lens will be, respectively (NEET 2025)
Option 1) $p^4$ and $m^4$
Option 2) $4p$ and $4m$
Option 3) $p^4$ and $4m$
Option 4) $4p$ and $m^4$
Chapter: Ray Optics and Optical Instruments
Correct Answer: Option 4
Explanation:
The total power of lenses in contact
$P_{total}=p+p+p+p=4p$
The total magnification
$m_{total}=m\times m\times m\times m=m^4$
Hence, the answer is option (4).
Ques: 8
The electron concentration in an n-type semiconductor is the same as the hole concentration in a p-type semiconductor. An external electric field is applied across each of them. Compare the currents in them. (NEET 2022)
Option 1) Current in n-type = current in p-type
Option 2) Current in p-type > current in n-type
Option 3) Current in n-type < current in p-type
Option 4) No current will flow in p-type, current will only flow in n-type
Chapter: Semiconductor Electronics
Correct Answer: Option 1
Explanation:
In both n-type and p-type semiconductors, electric current is due to drift motion of charge carriers when an electric field is applied.
Current in n-type = current in p-type
Hence, the answer is option (1).
Ques: 9
Consider the following statements (A) and (B) and identify the correct answer:
(A) A Zener diode is connected in reverse bias when used as a voltage regulator
(B) The potential barrier of the p–n junction lies between 0.1 V to 0.3 V (NEET 2021)
Option 1) (A) and (B) are correct
Option 2) (A) and (B) are incorrect
Option 3) (A) is correct and (B) is incorrect
Option 4) (A) is incorrect but (B) is correct
Chapter: Semiconductor Electronics
Correct Answer: Option 3
Explanation:
A Zener diode is always connected in reverse bias when used as a voltage regulator.
The potential barrier of a p–n junction is approximately 0.7 V for silicon and 0.3 V for germanium.
Hence, the answer is option (3).
Ques: 10
A 2 A current is flowing through two different small circular copper coils having a radius ratio of $1:2$. The ratio of their respective magnetic moments will be (NEET 2025)
Option 1) $4:1$
Option 2) $1:4$
Option 3) $1:2$
Option 4) $2:1$
Chapter: Moving Charges and Magnetism
Correct Answer: Option 2
Explanation:
Magnetic moment
$M=IA=I\pi r^2$
$\frac{M_1}{M_2}=\frac{I\pi r_1^2}{I\pi r_2^2}=\left(\frac{r_1}{r_2}\right)^2=\left(\frac{1}{2}\right)^2=\frac{1}{4}$
Hence, the answer is option (2).
Top 50 Physics Numericals in NEET That Guarantee 120+ Marks - Direct Download Link
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