NEET Physics Mock Test 2027: Download PDF Physic Practice Test

NEET 2027 Physics Mock Test PDF Free Download

You can download the NEET Physics Mock Test 2027 PDF for free from the table below. The mock test contains NEET level physics questions with detailed explanations of answers, chapter-wise practice sets and full-length tests based on the latest syllabus and exam pattern.

Why NEET Exam Mock Test is Important For Students?

For any NEET aspirant, the mock test is not just an option but a requirement. Due to the fact that NEET is a highly competitive exam, even minor errors can make an impact on ranks and college selection. The Mock Test helps students gain safe practice and thus improves their skills in terms of speed, accuracy and remaining calm during an exam. Preparation is not only about learning theoretical materials; rather, it is about using the knowledge within a certain time frame. Mock Tests are important because:

• Simulate real NEET exam conditions
• Improve speed and accuracy
• Help identify weak topics
• Decrease silly mistakes and negative marking
• Boost confidence under stress
• Increase formula application

NEET 2027 Physics Mock Test Questions and Solutions

Students may attempt the NEET Physics 2027 mock test that is freely available online and developed by experts from Careers360. After completing the test, students can review the detailed solutions to their mistakes. Also, the NEET 2027 mock test Physics PDF with questions, answers, and solutions is available to download below. Students can practise the top 50 physics numericals in NEET that guarantee 120+ marks. In the meantime, here are some sample NEET 2027 Physics questions to help students practice better.

Q.1 The dimensions $[ML{T}^{-2}{A}^{-2}]$ belong to:

1. Self-inductance
2. Magnetic permeability
3. Electric permittivity
4. Magnetic flux

Solution:

We know that the force per unit length between two current-carrying conductors is

$\frac{F}{l}=\frac{{\mu }_0{i}_1{i}_2}{2\pi a}$

Therefore,

$[{\mu }_0]=\frac{[F][a]}{[i_1][i_2][l]}$

or,

$[{\mu }_0]=[ML{T}^{-2}{A}^{-2}]$

Hence, the correct answer is Option (2) Magnetic permeability.

Q.2 A ball is thrown vertically downward with a velocity of $20\text{m/s}$ from the top of a tower. It hits the ground with a velocity of $80\text{m/s}$. The height of the tower is $(g=10{\text{m/s}}^2)$:

1. 360 m
2. 340 m
3. 320 m
4. 300 m

Solution:

Using the equation of motion,

$v^2-u^2=2as$

Substituting the values,

${80}^2-{20}^2=2\times 10\times h$

$6400-400=20h$

$6000=20h$

$h=300\text{m}$

Hence, the correct answer is Option (4) 300 m.

Q.3 A force $F=20+10y$ acts on a particle in the $y$-direction, where $F$ is in newtons and $y$ is in metres. The work done by this force to move the particle from $y=0$ to $y=1$ is:

1. 30 J
2. 5 J
3. 25 J
4. 20 J

Solution:

The work done by a variable force is

$W=\int Fdy$

Given,

$F=20+10y$

Therefore,

$W={\int }_0^1(20+10y)dy$

$W={\int }_0^{1}20dy+{\int }_0^{1}10ydy$

$W=20y{|}_0^1+5y^2{|}_0^1$

$W=(20\times 1-20\times 0)+(5\times 1^2-5\times 0^2)$

$W=20+5$

$W=25\text{J}$

Hence, the correct answer is Option (3) 25 J.

Q.4 The efficiency of a Carnot engine depends upon:

1. The temperatures of the source and sink
2. The volume of the cylinder of the engine
3. The temperature of the source only
4. The temperature of the sink only

Solution:

The efficiency of a Carnot engine is given by

$\eta =1-\frac{T_2}{T_1}$

where $T_1$ is the source temperature and $T_2$ is the sink temperature.

Since the efficiency depends on both $T_1$ and $T_2$, the correct answer is Option (1) The temperatures of the source and sink.

Q.5. The radius of the circle, the period of revolution, the initial position, and the sense of revolution are indicated in the figure.

The y-projection of the radius vector of the rotating particle P is:

1. $y(t)=-3\cos (2\pi t)$

2. $y(t)=4\sin \left(\frac{\pi t}{2}\right)$

3. $y(t)=3\cos \left(\frac{3\pi t}{2}\right)$

4. $y(t)=3\cos \left(\frac{\pi t}{2}\right)$

Solution:

At $t=0$, the position of the particle is $3\text{cm}$.

The angular displacement is given by

$\omega t=2\pi ft=\frac{2\pi t}{T}$

where the time period is $T=4\text{s}$.

Therefore,

$\omega t=\frac{2\pi t}{4}=\frac{\pi t}{2}$.

Since the amplitude is $3\text{cm}$ and the particle starts from the extreme position, the y-projection is

$y(t)=3\cos \left(\frac{\pi t}{2}\right)$.

Hence, the correct answer is Option (4).

NEET Physics Chapter Wise Weightage 2027

Knowing the chapter-wise weightage for NEET will aid candidates' success in the test. To make a strong plan for the exam day, check the chapter-wise weightage for NEET Physics and get the benefit of better and chapter-focused preparation. The following is the chapter wise weightage analysis on the basis of last year’s data.

It is the first thing that one must do to prepare effectively. Through this NEET Physics weightage analysis, one can learn about important chapters for NEET 2027.