2 Questions around this concept.
In a Fresnel's Biprism experiment Interference Fringes are observed with a biprism of refracting angle 2° and refractive index 1.5 on a screen which is 100m away from the source. If the distance between the source and the biprism is 20m and the Fringes width is 0.10 mm what is the wavelength of light ?

Let the separation between $S_1$ and $S_2$ be $d$ and the distance of slits and the screen from the biprism be a and b respectively i.e. $D=(a+b)$. If angle of prism is $A$ and refractive index is $\mu$ then $d=2 a(\mu-1) A$
$$
\lambda=\frac{\beta[2 a(\mu-1) A]}{(a+b)} \Rightarrow \beta=\frac{(a+b) \lambda}{2 a(\mu-1) A}
$$
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