NEET Preparation Of Aldehydes Concepts, Questions And Solutions

NEET Preparation Of Aldehydes Concepts, Questions And Solutions

Sumit SainiUpdated on 26 Jun 2022, 09:27 AM IST

Chemistry is one of the most scoring subjects in the National Eligibility cum Entrance Test (NEET), having a weightage of 25 percent out of three subjects – Chemistry, Physics and Biology which, in turn, includes Zoology and Botany. Considering the high NEET cut-offs in recent years, it is inevitable to prepare Chemistry in a comprehensive manner along with special focus on important topics.

This Story also Contains

  1. Analysis :
  2. Preparation of Aldehydes
  3. 1. By Oxidation Of Alcohol
  4. 2. Dehydrogenation Of Alcohols
  5. 3. From Hydrocarbons
  6. 4. From Acyl Chloride
  7. 5. From Nitriles And Esters:
  8. 6. From Hydrocarbons
NEET Preparation Of Aldehydes Concepts, Questions And Solutions
Aldehyde Preparation(Image:Shutterstock)

Analysis :

In the last five years of NEET examination, there have been three direct questions from the topic “Preparation of Aldehydes” and many indirect questions. Some of the questions are discussed in detail towards the end of this article. The Questions asked on this topic are moderate to difficult. From the questions it can be concluded that one must memorise the reactions in order to solve the questions. Questions from this topic are based on the reaction mechanism in which reagent, intermediate or final product is asked. The topic “Preparation of Aldehydes” mainly belongs to the chapter Aldehydes, ketones and Carboxylic acids. However some of the portion of this topic is also discussed in the chapter “Alcohols, Phenols and Ethers”.

Preparation of Aldehydes

In organic Chemistry, the compounds having carbon-oxygen double bonds are known as Carbonyl compounds. Carbonyl group in Organic Chemistry is one of the most prevalent functional groups. Carbonyl functional group is predominantly found in Aldehydes and Ketones. Aldehydes are the compounds in which the Carbonyl group is attached to carbon and hydrogen whereas Ketones are compounds in which two Carbon atoms are attached to the Carbonyl group. In this article, we will be discussing mainly Aldehydes and their method of Preparation. Preparation of Aldehydes is an important topic for competitive examinations like JEE and NEET. Let’s discuss various methods of preparation of Aldehydes.

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Preparation of Aldehydes can be undertaken through various methods depending upon the type of compound required. However, from the exam perspective and NCERT syllabus, we have some of the important reactions which are discussed below.

1. By Oxidation Of Alcohol

Oxidation of Alcohol is one of the prominent methods to prepare Aldehydes. However this can be achieved by Oxidation of primary alcohols only as in case of secondary alcohols, Ketones are formed. Below is the depiction of the preparation of Aldehydes via oxidation of Primary alcohols. Also preparation of Ketones is shown using secondary alcohol to understand the difference in oxidation product between primary and secondary alcohols.

The oxidation process in alcohol consists of the formation of a carbon-oxygen double bond and the cleavage of an O-H and C-H bonds as shown in the figure below.

1655972469164

The above mentioned processes of cleavage and formation of bonds occur in oxidation reactions. As it is clear from the above reaction, loss of dihydrogen takes place from alcohol molecules, hence this reaction is also known as dehydrogenation reaction.

For the Preparation of Aldehydes, oxidising agent used is CrO3 in anhydrous medium.

1655972500670

Another reagent which can be used for the oxidation of primary alcohols to Aldehydes is pyridinium chlorochromate (PCC), a complex of chromium trioxide with pyridine and HCl which is shown below.

1655972474719

Secondary alcohols are oxidized to ketone by chromic anhydride (CrO3 ) as shown below,

1655972474870

Apart from the primary and secondary alcohol oxidation, which are discussed above, Tertiary alcohols generally do not undergo oxidation reaction under normal conditions.

2. Dehydrogenation Of Alcohols

Dehydrogenation method to prepare alcohol is suitable for industrial application. In this method alcohol vapours are passed over metal catalysts like Ag or Cu such that the product obtained is an aldehyde. In this case also, Primary and secondary alcohols give Aldehydes and ketones, respectively. Below mentioned is the reaction depicting Dehydrogenation of Alcohols in which the vapours of a primary or a secondary alcohol are passed over heated copper at 573 K, dehydrogenation takes place and an aldehyde or a ketone is formed.

1655972490707

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3. From Hydrocarbons

Formation of Aldehydes is undertaken by the ozonolysis of alkenes followed by reacting the ozonolysis products with zinc dust and water. In ozonolysis method, addition of ozone molecules to alkene takes place leading to formation of ozonide, after that cleavage of the ozonide by Zn-H2O to smaller molecules takes place. In ozonolysis reaction, a mixture of Aldehydes and ketones is obtained depending upon the structure of the hydrocarbon. Below mentioned are the reactions, in which ozonolysis product is shown which includes both Aldehydes and ketones depending on the reactant taken.


1655972501245

4. From Acyl Chloride

In this reaction, Acid chloride is passed over a catalyst like palladium on barium sulfate to obtain Aldehyde. This reaction is called Rosenmund reduction. Below is the representation of the reduction of acyl chloride in order to obtain aldehyde.

1655972479679

5. From Nitriles And Esters:

For the formation of Aldehydes, Nitriles are reduced to corresponding imine along with stannous chloride in the presence of hydrochloric acid, which on further hydrolysis give corresponding aldehyde. This reaction is known as the Stephen reaction. Below is the reaction representation of Stephen's reaction.

1655972475155

Similarly, to produce Aldehydes, esters are also reduced to Aldehydes with DIBAL-H which is shown below in the reaction.

1655972483851

6. From Hydrocarbons

This method is used to prepare aromatic Aldehydes from aromatic hydrocarbons.

Below are some of the methods to prepare aromatic Aldehydes.

a. By using chromyl chloride(CrO2Cl2):

In the process of formation of Benzaldehyde, Chromyl chloride (CrO2Cl2 ) is used in which Chromyl chloride oxidizes methyl groups to a chromium complex as shown in the reaction below, which on hydrolysis gives corresponding benzaldehyde.

This reaction is known as the Etard reaction.

1655972483706

b. By side chain chlorination followed by hydrolysis

This method is also known as the commercial method to manufacture benzaldehyde in which toluene is treated with chlorine in presence of UV light which leads to Side chain chlorination of toluene giving benzal chloride as shown in the reaction below. On further hydrolysis of benzal chloride, it gives benzaldehyde. Below is the reaction showing step-by-step formation of Benzaldehyde.

1655972483535

c. By Gatterman –Koch reaction

For the preparation of aromatic aldehyde, an important reaction is Gatterman-Koch reaction in which benzene or benzene derivative is treated with carbon monoxide and hydrogen chloride in the presence of anhydrous aluminum chloride or cuprous chloride which gives benzaldehyde or substituted benzaldehyde. Below is the Gatterman-Koch reaction.

1655972475448

This reaction is Called Gatterman-Koch reaction.

Above discussed are some of the most important methods of preparation of Aldehydes. Students are advised to understand the above reactions in a logical manner and try to memorize the reactants, products and the reagents used in order to identify the reaction in the examination.

Below are some of the questions asked in NEET in the last 5 years from the topic “Preparation of Aldehydes”. Students should practice these questions by themselves after completing the theory in order to assess the difficulty level and type of questions asked in the NEET exam from this topic.

Q1. The Intermediate compound 'X' in the following chemical reaction is : [NEET 2021]

1655972486196

  1. 1655972482176

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  1. 1655972484125

  2. 1655972483989

  3. 1655972484252


Solution. The reaction will be -

1655972507314

Therefore, option 1 is correct.

Q2. Identify the major products P, Q and R in the following sequence of reactions : [NEET 2018]

1655972449528

  1. 1655972479002

  2. 1655972448450

  3. 1655972448868

  4. 1655972448644

Solution. The reaction will be -

Due to Cl being a good leaving group, it will leave the alkane in the presence of anhydrous AlCl3 and forms 1-degree carbonation then convert to 2-degree carbocation.

1655972494857

Hence option 4 is correct.

Q3. Compound A, C8H10O, is found to react with

NaOI (produced by reacting Y with NaOH and yields a yellow precipitate with characteristic smell.

A and Y are respectively [NEET 2018]

  1. 1655972464384

  2. 1655972486489

  3. 1655972486372

  4. 1655972484692

Solution.

As we learnt in

Haloform Reaction -

CH_{3}COR\:\:is\:oxidised\:by\:\:NaOI\:\:to\:form\:iodoform\:and\:\:RCO_{2}Na

- wherein

C_{2}H_{5}COCH_{3}+NaOH+I_{2}\rightarrow C_{2}H_{5}CO_{2}Na+CHI_{3}

1655972491184

Hence Option 1 is correct

Q4. Consider the reactions: [NEET 2017]

1655972508578

Identify A, X, Y and Z.

  1. A-Methoxymethane, X-Ethanoic acid, Y-Acetate ion, Z-hydrazine.

  2. A-Methoxymethane, X-Ethanol, Y-Ethanoic acid, Z-Semicarbazide.

  3. A-Ethanal, X-Ethanol, Y-But-2-enal, Z-Semicarbazone.

  4. A-Ethanol, X-Acetaldehyde, Y-Butanone, Z-Hydrazone.

Solution. As we learnt in

Addition of ketones with alcohols -

Produces an unstable hemiketal intermediate and further stable compound called ketal.

- wherein

1655972508431

and

Addition of ammonia and its derivatives with aldehydes and ketones -

Product formation is favoured due to rapid dehydration of the intermediate to form > C = NG

G\:\:may\:be\:\:-OH,\:\:-NH_{2},\:\:-NHC_{6}H_{5},\:\:-NHCONH_{2},\:\:etc

- wherein1655972510778

and

Aldol condensation -

Aldehydes and ketones possessing \alpha - hydrogen atom in the presence of dilute alkali undergo self-condensation to form \beta - hydroxy aldehyde and

\beta - hydroxy ketone.

- wherein1655972511123

1655972510981

Hence option 3 is correct.

In the above article, we have discussed in detail the importance of the topic “Preparation of Aldehydes” for the NEET examination. This article can be referred by the students for the last minute revision as it includes all the important reactions which are related to Preparation of Aldehydes along with the question asked in the Previous years.

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Questions related to NEET

On Question asked by student community

Have a question related to NEET ?

First, understand the NEET syllabus clearly for Physics, Chemistry, and Biology. Focus only on the NCERT syllabus, as most NEET questions are directly or indirectly based on NCERT, especially in Biology and Chemistry. Avoid unnecessary reference books at this stage.

Divide your 4 months into phases. In the first 2 months, focus on completing the entire syllabus. Study Biology daily, as it carries the highest weightage. Read NCERT Biology line by line, make short notes, and revise regularly. For Chemistry, give priority to NCERT for Inorganic and Organic Chemistry. Practice basic numericals and reactions consistently. In Physics, focus on understanding concepts and practicing standard questions rather than memorizing formulas.

In the third month, start intensive revision along with topic-wise and full-length mock tests. Analyze each test carefully to identify weak areas and work on them. Improve time management and accuracy during this phase.

In the last month, focus mainly on revision and mock tests. Revise NCERT multiple times, especially Biology diagrams, tables, and examples. Avoid learning new topics at the last moment. Maintain a proper sleep schedule and take short breaks to avoid burnout.

Stay consistent, avoid distractions, and believe in your preparation. Even a few focused hours daily with proper planning can make a big difference. All the best!

Scoring 600+ marks in NEET within 4 months is definitely challenging, especially if you are starting almost from scratch, but it is not impossible. It largely depends on your discipline, daily study hours, clarity of basics, and how smartly you plan your preparation.

First, you need to be very realistic and focused. In 4 months, your main goal should be to strengthen NCERT-based concepts rather than trying to study everything in extreme detail. NEET questions are largely NCERT-oriented, especially in Biology and Chemistry. If you can master NCERT thoroughly, your chances improve significantly.

Biology should be your top priority because it carries the maximum weightage and is comparatively scoring. Read NCERT line by line for both Class 11 and 12. Revise multiple times and practice MCQs daily. Even if Physics feels tough initially, focus on high-weightage and formula-based chapters like Modern Physics, Current Electricity, Semiconductors, Ray Optics, and Laws of Motion. Chemistry can be divided smartly: give more time to Organic and Inorganic NCERT, and practice numericals regularly for Physical Chemistry.

You should ideally study 10–12 focused hours daily with a fixed timetable. Daily revision and weekly full-length mock tests are extremely important. Initially, your mock scores may be low, but what matters is consistent improvement and learning from mistakes. Analyze each test carefully to understand weak areas.

Since you are already enrolled in another college, time management becomes even more important. Try to minimize distractions and use early mornings or late evenings effectively. Avoid too many reference books; stick to NCERT and one reliable question bank.

That said, aiming for 600+ in 4 months is ambitious and depends on your learning speed and consistency. Even if you fall slightly short, a strong score improvement can still open opportunities in government or private colleges depending on category and cutoff trends.

Stay disciplined, trust the process, and do not compare your journey with others. Many students have made significant jumps in short durations with focused effort. All the best.

Hello,

Here are the important naming reactions for the NEET preparation.

Naming Reaction for NEET Preparation

Hope it helps your preparation. Good luck.


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