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Chemical Kinetics is one of the important chapters of class 12 Chemistry. It generally deals with understanding the rate of chemical reactions. Rate of chemical reaction is the speed at which chemical reaction takes place. Reaction rate is influenced by many factors including temperature, pressure, catalyst etc.
For NEET UG 2025, candidates from all categories must be born on or before December 31, 2008, to meet the lower age limit. NTA has confirmed that there is no upper age limit, as per a letter from the National Medical Commission (NMC) and the Under Graduate Medical Education Board (UGMEB).
Reactions are classified in various orders like zero order reaction, First order reaction, second order reaction among others on the basis of rate law followed by them.
A first-order reaction refers to the reaction in which the rate of reaction is proportional to the first power of concentration of the reactant at any point of time. Hence, higher the concentration of reactant, higher will be the rate of reaction. Rate of first order reaction decreases as it proceeds due to decrease in concentration of reactant.
Hence in first order reaction, rate of reaction is directly proportional to the concentration of reactant as described in the equation below.
Reaction-
Reactant →Product
Rate =k[Reactant]
Below are some of the examples of First Order reaction
2N2O5 → 4NO2+O2
Rate = k[N2O5]
2H2O2 → 2H2O + O2
Rate = k[H2O2]
After analysing the last five years of NEET papers, it has been observed that, total 10 questions were asked from the Chemical Kinetics Chapter and out of those, four questions belong to First order reaction. This shows that First order reaction is the most important concept of Chemical Kinetics and most of the questions can be solved if Integral form of first order reaction is understood well. Questions asked from first order reactions are discussed in the article below.
Differential Rate Law for a First-Order Reaction reflects the change in concentration with respect to time which is shown by equation below:
Let us assume a first order reaction: A(Reactant)→B(Product)
Rate = -d[A]/dt = k[A]1 = k[A]
In the above equation,
‘k’ represents the rate constant of the first-order reaction, the unit of the rate constant is s-1.
‘[A]’ represents the concentration of the reactant.
d[A]/dt represents the change in the concentration of reactant ‘A’ with respect to time.
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Integrated Rate Law of first order reaction is used to calculate the value of rate of rate constant, concentration of reactant a given time, half life etc. Most of the numericals are solved by using Integrated rate law only. Differential rate law is used to obtain the Integral rate law of a First order reaction.
Differential rate law is: -d[A]/dt = k[A]
d[A]/dt = -k[A]
Integrating both sides, we get
Where [A]o is concentration of reactant at time t0 s, and [A] is the concentration of reactant at time t. We get,
Considering t0 =0, and solving the equation, we get
ln[A] – ln[A]0 = -kt
ln[A] =ln[A]0 -kt
Raising each side to component e, we get
Hence, is the final expression in the integrated form for first order reaction. The above derivation is useful in solving many numerical problems.
Using the Integrated Rate law, Concentration v/s time Graph for First order reaction can be obtained which is shown below
As the first-order reaction follows the equation ln[A] = ln[A]0 – kt which is similar to that of a straight line (y = mx + c) with slope -k. Hence, this equation can be plotted as-
From the above graph, it can be said that the graph for ln[A] v/s t for a first-order reaction is a straight line with slope -k.
The half-life of a chemical reaction refers to the time required by the reactant concentration to become half of its initial value. It is represented by .
Hence, according to the first order reaction, . Where [A] refers to the concentration of the reactant at any time ‘‘t’’ and [A]o represents the initial concentration of the reactant.
At half life, t = t1/2 , [A] =A0/2
Putting the value of [A] =A0/2 and t = t1/2 in the equation , we get
Taking ln on both sides, we get,
Hence half life of the first order reaction is 0.693/k, where k is the rate constant.
Below discussed are some of the questions asked in the NEET exam from first order reaction.
Question 1. A first order reaction has a specific reaction rate of 10-2 sec-1. How much time will it take for 20 g of the reactant to reduce to 5 g? [NEET 2017]
238.6 sec
138.6 sec
346.5 sec
693.0 sec
Ans. The rate of first order reaction is proportional to the first power of the concentration of the reaction.
Let us consider a reaction, R → P , wherein
R → P
At t=0 a 0
At t=t a-x x
After solving this equation, we get
Now, putting the values
t= 138.6 sec
Alternatively, this can be solved by the half life method. According to which after the first half life concentration becomes half and after the second half life, concentration becomes ¼ th of the initial concentration. Hence after two half life, the concentration becomes from 20g to 5g.
Now, 2t1/2= 69.3×2= 138.6 sec.
Hence option ‘’C’’ is correct.
Question 2. The correct difference between first and second-order reactions is that [NEET 2018]
a first-order reaction can be catalysed; a second-order reaction cannot be catalysed
the half-life of a first-order reaction does not depend on [A]o; the half-life of a second-order reaction does depend on [A]o
the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
Ans. For first Order reaction, rate is directly proportional to the first power of concentration.
For a reaction, A→B
Rate = -d[A]/dt = k[A] and half life is
Where unit of .
Hence
For second order reaction, For a reaction, A→B
Rate = and its half life is
Hence, The half-life of a first-order reaction does not depend on [A]o; the half-life of a second-order reaction does depend on [A]o
Option B is correct.
Question 3. If the rate constant for a first order reaction is k, the time (t) required for the completion of 99 per cent of the reaction is given by: [NEET 2019]
t = 0.693/k
t = 6.909/k
t = 4.606/k
t = 2.303/k
Ans. Let us consider a reaction, R → P , wherein
R → P
At t=0 a 0
At t=t a-x x
For the First Order reaction, Rate of reaction is proportional to the first power of the concentration of the reaction.
Unit of
and
Hence option C is correct.
Question 4. The rate constant for a first order reaction is The time required to reduce 2 g of the reactant to 0.2g is: [NEET 2020]
1000s
100s
200s
500s
Ans. Given,
Hence the given reaction is of first order.
Thus, we have:
Hence it is from the option of keeping th
Thus,
Therefore, Option(D) is correct.
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To fully prepare for NEET :
1. Master NCERTs – Focus on Biology, Physics and Chemistry from NCERT.
2. Consistent Study – Study 6-8 hours daily with a well-structured plan.
3. Practice Regularly – Solve PYQs, mock tests and improve speed & accuracy.
4. Conceptual Clarity – Use reference books for Physics & Chemistry.
5. Revision & Notes – Revise regularly and make short notes for quick recall.
Stay Healthy & Focused – Eat well , sleep properly and stay motivated.
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Taking a drop year to prepare for NEET can be a strategic move. Here's a suggested plan for you:
2025 (Drop Year)
1. Create a study schedule: Plan out your day, week, and month to ensure consistent studying.
2. Focus on weak areas: Identify your weaknesses and concentrate on improving those subjects.
3. Join a coaching institute or online course: Consider enrolling in a reputable coaching institute or online course to supplement your studies.
4. Practice with sample papers and mock tests: Regularly practice with sample papers and mock tests to assess your progress and identify areas for improvement.
5. Stay motivated: Remind yourself why you're taking this drop year, and celebrate small victories along the way.
2026 (NEET Year)
1. Intensify your preparation: Increase your study hours and focus on refining your concepts.
2. Take mock tests regularly: Regularly take mock tests to assess your performance and identify areas for improvement.
3. Stay updated with the NEET syllabus: Ensure you're familiar with the latest NEET syllabus and exam pattern.
4. Stay healthy and focused: Take care of your physical and mental health by exercising regularly, eating well, and getting enough sleep.
Additional Tips
1. Seek guidance: Consult with teachers, mentors, or counselors to get guidance on your preparation.
2. Stay positive: Believe in yourself and your abilities, and stay positive throughout your preparation journey.
3. Be flexible: Be prepared to adjust your study plan if needed, and don't be too hard on yourself if you encounter setbacks.
By following this plan, you'll be well-prepared for NEET 2026. Stay focused, motivated, and committed to your goals!
To qualify for NEET 2025:
Nationality: Indian citizens, NRIs, OCIs, PIOs, and foreign nationals are eligible.
Age Limit: Minimum 17 years (as of Dec 31, 2025); no upper age limit.
Education: Must have passed or be appearing for Class 12 with Physics, Chemistry, Biology/Biotechnology, and English.
Minimum Marks:
General: 50% in PCB
SC/ST/OBC: 40% in PCB
PwD: 40% in PCB
Attempts: No limit on the number of attempts.
Qualifying Exam Code: Must be chosen correctly in the application.
Candidates should check all criteria before applying to avoid disqualification.
To qualify for NEET 2025:
Nationality: Indian citizens, NRIs, OCIs, PIOs, and foreign nationals are eligible.
Age Limit: Minimum 17 years (as of Dec 31, 2025); no upper age limit.
Education: Must have passed or be appearing for Class 12 with Physics, Chemistry, Biology/Biotechnology, and English.
Minimum Marks:
General: 50% in PCB
SC/ST/OBC: 40% in PCB
PwD: 40% in PCB
Attempts: No limit on the number of attempts.
Qualifying Exam Code: Must be chosen correctly in the application.
Candidates should check all criteria before applying to avoid disqualification.
According to the NEET eligibility criteria:
Eligibility Criteria
- A candidate who has failed in Class 12th examination but has cleared it as a private candidate is eligible to appear for NEET.
- However, the candidate must have passed Class 12th or equivalent examination with Physics, Chemistry, Biology/Biotechnology, and English as core subjects.
Conditions
- The candidate must have passed the Class 12th examination or equivalent with the required subjects (Physics, Chemistry, Biology/Biotechnology, and English) in the first attempt.
- If the candidate has passed the Class 12th examination or equivalent as a private candidate, they must have passed the examination with the required subjects in the first attempt.
Important Note
- It's essential to check the NEET eligibility criteria and the specific requirements of the medical colleges you're applying to, as they may have additional eligibility criteria.
In summary, a student who failed in Class 12th examination but cleared it as a private candidate is eligible to appear for NEET, provided they meet the required eligibility criteria.
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