Important Chemistry Formulas For NEET 2025 Exam- Topic-wise Formulas PDF

Important Chemistry Formulas For NEET 2025 Exam- Topic-wise Formulas PDF

Edited By Irshad Anwar | Updated on Nov 21, 2024 09:22 AM IST | #NEET

Important Chemistry Formulas for NEET: Are you preparing for the NEET UG 2025 exam? Are you ready to enter one of India's top medical colleges by passing the National Eligibility and Entrance Test (NEET)? Master the NEET 2025 chemistry formula sheet to score high in the NEET exam. Here, we are providing the NEET chemistry formula sheet pdf 2025, topic-wise, that every NEET aspirant needs to know. From physical chemistry, and organic chemistry to inorganic chemistry, we've got all the chemistry imp formulas for NEET exam preparation 2025. Enhance your NEET preparation and boost your confidence with this chemistry formula sheet for NEET PDF 2024 Continue reading to discover the secrets to cracking NEET Chemistry in 2025.

NEET 2024: Cutoff (OBC, SC, ST & General Category)

NEET 2024 Admission Guidance: Personalised | Study Abroad

NEET 2025: SyllabusMost Scoring concepts NEET PYQ's (2015-24)

NEET PYQ's & Solutions: Physics | ChemistryBiology

Important Chemistry Formulas For NEET 2025 Exam- Topic-wise Formulas PDF
Important Chemistry Formulas For NEET 2025 Exam- Topic-wise Formulas PDF

NTA conducts the NEET Exam once a year. Understanding chemistry concepts such as stoichiometry, thermodynamics, and kinetics requires a solid grasp of equations and reactions and NEET chemistry formulas, which are important components of the NEET exam. NEET aspirants should know that studying important chemistry formulas for NEET and equations during the last-minute revision before an exam matters greatly. In the extremely competitive NEET exam, every mark counts. If students have a solid understanding of the NEET chemistry formula sheet pdf, they can easily secure marks on formula-based questions, which are often simple.

Finally, mastering these equations and reactions and NEET chemistry important formulas from the Chemistry NEET 2025 formula sheet enhances confidence, accuracy, efficiency, and problem-solving skills. These are necessary qualities for passing the NEET exam. We have compiled a chemistry formula sheet for NEET PDF from the top 11 most-scoring concepts in physics on the NEET syllabus. This formula sheet for the chemistry NEET will guide those preparing for the NEET exam 2025 in their last-minute preparation.

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Chemistry Formula Sheet for NEET PDF 2025

  1. Shapes Of Molecules

Most Scoring concepts for NEET
This ebook serves as a valuable study guide for NEET exams, specifically designed to assist students in light of recent changes and the removal of certain topics from the NEET exam.
Download EBook

The ideal shapes of molecules, which are predicted based on electron pairs and lone pairs of electrons, are mentioned in the table below:

A table is shown that is comprised of six rows and six columns. The header row reads: “Number of Electron Pairs,” “Electron pair geometries; 0 lone pair,” “1 lone pair,” “2 lone pairs,” “3 lone pairs,” and “4 lone pairs.” The first column contains the numbers 2, 3, 4, 5, and 6. The first space in the second column contains a structure in which the letter E is single bonded to the letter X on each side. The angle of the bonds is labeled with a curved, double headed arrow and the value, “180 degrees.” The structure is labeled, “Linear.” The second space in the second column contains a structure in which the letter E is single bonded to the letter X on three sides. The angle between the bonds is labeled with a curved, double headed arrow and the value, “120 degrees.” The structure is labeled, “Trigonal planar.” The third space in the second column contains a structure in which the letter E is single bonded to the letter X four times. The angle between the bonds is labeled with a curved, double headed arrow and the value, “109 degrees.” The structure is labeled, “Tetrahedral.” The fourth space in the second column contains a structure in which the letter E is single bonded to the letter X on five sides. The angle between the bonds is labeled with a curved, double headed arrow and the values “90 and 120 degrees.” The structure is labeled, “Trigonal bipyramid.” The fifth space in the second column contains a structure in which the letter E is single bonded to the letter X on six sides. The angle between the bonds is labeled with a curved, double headed arrow and the value, “90 degrees.” The structure is labeled, “Octahedral.” The first space in the third column is empty while the second contains a structure in which the letter E is single bonded to the letter X on each side and has a lone pair of electrons. The angle between the bonds is labeled with a curved, double headed arrow and the value, “less than 120 degrees.” The structure is labeled, “Bent or angular.” The third space in the third column contains a structure in which the letter E is single bonded to the letter X three times and to a lone pair of electrons. It is labeled with a curved, double headed arrow and the value, “less than 109 degrees.” The structure is labeled, “Trigonal pyramid.” The fourth space in the third column contains a structure in which the letter E is single bonded to the letter X on four sides and has a lone pair of electrons. The bond angle is labeled with a curved, double headed arrow and the values, “less than 90 and less than 120 degrees.” The structure is labeled, “Sawhorse or seesaw.” The fifth space in the third column contains a structure in which the letter E is single bonded to the letter X on five sides and has a lone pair of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “less than 90 degrees.” The structure is labeled, “Square pyramidal.” The first and second spaces in the fourth column are empty while the third contains a structure in which the letter E is single bonded to the letter X on each side and has two lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “less than less than 109 degrees.” The structure is labeled, “Bent or angular.” The fourth space in the fourth column contains a structure in which the letter E is single bonded to the letter X three times and to two lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “less than 90 degrees.” The structure is labeled, “T - shape.” The fifth space in the fourth column contains a structure in which the letter E is single bonded to the letter X on four sides and has two lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value “90 degrees.” The structure is labeled, “Square planar.” The first, second and third spaces in the fifth column are empty while the fourth contains a structure in which the letter E is single bonded to the letter X on each side and has three lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “180 degrees.” The structure is labeled, “Linear.” The fifth space in the fifth column contains a structure in which the letter E is single bonded to the letter X three times and to three lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “less than 90 degrees.” The structure is labeled, “T - shape.” The first, second, third, and fourth spaces in the sixth column are empty while the fifth contains a structure in which the letter E is single bonded to the letter X on each side and has four lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value “180 degrees.” The structure is labeled, “Linear.” All the structures use wedges and dashes to give them three dimensional appearances.

  1. Solubility And Solubility Products

General Representation
\mathrm{A_xB_y} \rightleftharpoons \mathrm{xA}^{+y}+\mathrm{yB}^{-\mathrm{x}}

\mathrm{Ksp =[ A^{+y}]^x \times[ B^{-x}]^y}

Relation between Solubility(s) and Solubility Product (Ksp)
\mathrm{A_xB_y} \rightleftharpoons \mathrm{xA}^{+y}+\mathrm{yB}^{-\mathrm{x}} s 0 0 - xs ys
\text { Thus, } \mathrm{Ksp = x ^{x} y ^{y}( s )^{ x + y }}

The Gas Laws- Boyle’s Law (Pressure-Volume Relationship) -

Also read:

  1. The Gas Laws- Boyle’s Law (Pressure-Volume Relationship)

    1714400387682

k1 is the proportionality constant whose value depends upon the following factors.

1714400387851 1714400387927


Relation between Density and Pressure

1714400388217

  1. Mathematical Analysis of Cubic System

Coordination Number (C. No.)

In Simple Cubic (SC): 6

In Face Centered Cubic (FCC): 12

In Body Centered Cubic (BCC): 8

Density of Lattice Matter (d)

It is the ratio of mass per unit cell to the total volume of a unit cell and it is found out as follows.

\mathrm{d}=\frac{\mathrm{Z} \times \text { Atomic weight }}{\mathrm{N}_{0} \times \text { Volume of unit cell }\left(\mathrm{a}^{3}\right)}


Here, d = Density

Z = Number of atoms

N0 = Avogadro number

a3 = Volume

a = Edge length

To find the density of a unit cell in cm3, m must be taken in g/mole and should be in cm.

Radius Ratio

It is the ratio of the radius of an octahedral void to the radius of the sphere forming the close-packed arrangement Normally, ionic solids are more compact, as voids are also occupied by cation (smaller in size). The pattern of arrangements and type of voids both depend on the relative size (ionic size) of two ions in a solid.

For example, when r+ = r- the most probable and favourable arrangement is BCC type.

With the help of relative ionic radii, it is easier to predict the most probable arrangement. This property is expressed as radio ratio.

\mathrm{\text { Radius ratio }=\frac{r^{+} \text {(radius of cation) }}{r^{-} \text { (Radius of anion) }}}


From the value of the radius ratio, it is clear that the larger the radius ratio, the larger the size of the cation, and the more anions needed to surround it—that is, the more coordination numbers.

Radius ratio for tetrahedron

\begin{array}{l}{\text { Angle } A B C \text { is the tetrahedral angle of } 109.5^{\circ}} \\\\ {\angle A B D=\frac{109.5}{2}=5475^{\circ}} \\\\ {\text { In triangle } A B D} \\\\ {\text { Sin } A B D=0.8164=A D / A B} \\\\ {\text { or } \frac{r^{*}+r}{r}=\frac{1}{0.8164}=1.225} \\\\ {\text { or } \frac{r^{*}}{\Gamma}=0.225}\end{array}

1714400387372

Radius ratio for octahedron

\begin{array}{l}{\mathrm{AB}=\mathrm{r}^{+}+\mathrm{r}} \\\\ {\mathrm{BD}=\mathrm{r}} \\\\ {\angle \mathrm{ABC}=45^{\circ}} \\\\ {\text { In triangle } \mathrm{ABD}}\end{array}\\\\\\\begin{array}{l}{\operatorname{Cos} A B D=0.7071=B D / A B} \\\\ {=\frac{r}{r^{+}+r}} \\\\ {\text { or } \frac{r^{+}+r}{r}=\frac{1}{0.707}=1.414} \\\\ {\text { or } \frac{r}{r^{4}}=0.414}\end{array}


1714400388353

  1. Charge On Colloids

Colloidal particles always carry an electric charge. The nature of this charge is the same for all the particles in a given colloidal solution and may be either positive or negative.

  1. Oxidation State

An interesting feature in the variability of oxidation states of the d-block elements is noticed among the groups. Although in the p–block the lower oxidation states are favoured by the heavier members (due to the inert pair effect), the opposite is true in the groups of d-block.

Also read:

  1. Preparation Of Aldehyde

Rosenmund Reduction

1714400387289

Stephen Reduction
1714400387587

  1. Nucleophilic Addition Reaction:

(i) Mechanism of nucleophilic addition reactions:
1714400386979

1714400387462

  1. Reduction And Oxidation Reaction

Reduction to hydrocarbons:
The carbonyl group of aldehydes and ketones is reduced to the CH2 group on treatment with zinc amalgam and concentrated hydrochloric acid (Clemmensen reduction) hydrazine hydrazone or with hydrazine, followed by heating with sodium or potassium hydroxide in a high boiling solvent such as ethylene glycol (Wolff-Kishner reduction).

Oxidation
Aldehydes differ from ketones in their oxidation reactions. Aldehydes are easily oxidised to carboxylic acids on treatment with common oxidising agents like nitric acid, potassium permanganate, potassium dichromate, etc. Even mild oxidising agents, mainly Tollens’ reagent and Fehlings’ reagent, also oxidise aldehydes.

  1. Chemical Properties Of Carboxylic Acid:

Formation of Anhydride

1714400388411

Reaction with Ammonia
1714400388275

Reduction

1714400388475

Decarboxylation
1714400388616

Kolbe's electrolysis
1714400389110 Halogenation 1714400388672

Ring substitution
1714400389018

1714400388545

  1. Carbohydrates

Carbohydrates -

These are polyhydroxy aldehydes, ketones or substances that form these on hydrolysis and possess at least one chiral atom. The (-OH) group is available in the form of hemiacetals or hemiketals.

Classification:

Carbohydrates can be classified into three categories:

  1. Monosaccharides: They are the simplest carbohydrates which cannot be hydrolysed into smaller molecules. They are sweet and crystalline and are called sugars.

  2. Oligosaccharides: These carbohydrates, on hydrolysis, give two to nine molecules of monosaccharides classified as di-, tri, tetra-saccharides, etc. For example, sucrose, maltose, lactose, raffinose, etc. They are also called sugars.

  3. Polysaccharides: These carbohydrates, on hydrolysis, give a large number of monosaccharides, e.g., starch, cellulose, etc. They are also called non-sugars.

Reducing and Non-reducing Sugars
Those sugars which reduce Fehling's and Tollens's solutions are called reducing sugars and those which do not reduce these reagents are called non-reducing sugars.

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Questions related to NEET

Have a question related to NEET ?

Hello Kavya,

Here is an overview of your problem, and its solution :-

  1. Filling NEET Form

    • Eligibility : NEET requires you to have passed 12th with Physics, Chemistry, and Biology/Biotechnology from a recognized board. Your CBSE 12th result is sufficient.
    • Details to Fill : Use your CBSE 12th details for NEET application. Do not mention your UP Board private attempt at math if you're dropping it.
  2. Filling JEE Form

    • Eligibility : JEE requires Physics, Chemistry, and Mathematics in 12th. If you're dropping the UP Board Math exam, you won't meet this criterion, and applying for JEE won't be valid.
  3. Impact of Dropping UP Board Math

    • It won't affect your CBSE 12th result or eligibility for NEET because they're independent. Dropping the math exam simply means you won't qualify for math-related entrances like JEE.
  4. Simplify Your Decision

    • Focus on NEET if you're inclined towards medicine or biology-related fields.
    • Avoid confusion by leaving the UP Board math attempt officially incomplete; it won't interfere with your CBSE credentials.

Conclusion : Drop the math attempt without worry and focus on NEET preparation using your CBSE bio stream qualifications.

To know more about NEET and JEE for filling, visit :

1. How to fill NEET application form

2. How to fill JEE application form

Hope it helps !

Hello,

No, discontinuing your BSc course will not cause significant issues in NEET UG counselling, as long as you meet the eligibility criteria for NEET UG. Here are key points to consider:

  1. Eligibility for NEET UG :

    • Ensure you meet the minimum educational qualifications for NEET UG, i.e., 10+2 with required PCB (Physics, Chemistry, Biology) marks.
  2. Discontinued Course :

    • NEET counselling focuses on NEET scores and eligibility, not on past incomplete courses.
  3. Document Verification :

    • Carry your Class 10 and Class 12 certificates during counselling. Your BSc discontinuation certificate (CLC) may not be relevant unless specifically asked.
  4. Focus on NEET Scores :

    • Your NEET UG score and category rank hold primary importance.
  5. Explain if Needed :

    • If asked, you can explain your preparation decision for NEET UG clearly.

Prepare thoroughly for NEET UG and document requirements; your BSc status should not hinder your counselling process.

To know more, visit : NEET Eligibility Criteria

Hope it helps !

Yes, you can absolutely attempt NEET again even if you are currently in your first year of BSc Nursing in Belgaum, and being from Goa does not affect your eligibility to take the exam you can re-take NEET to pursue a medical degree (MBBS) if you wish to change your career path.

Ultimately, the decision to quit your current course and prepare for NEET should align with your passion and long-term career goals.

This link will help you in exam preparation

https://medicine.careers360.com/exams/neet

Best of luck for your future endeavours

Securing a government medical college seat through NEET needs an eligiblity and as per the eligibility if you are a student of final year BSc is eligible to participate in NEET counselling process and admission.


So if you fail in final year BSc exams it doesn't matter and if you secure a seat in a medical college you can take the admission without any problem.the only problem is the certificates you need to present at the time of document verification.if you fail to provide your documents your seat may get cancelled.

You need to collect your all documents from the college if they coperate you can get certificate easily but if not request them. If you are taking admission on the basis of 12th marks then it may create problem in future so try to get certificate from college.

Hope it helps..

Hello,

Yes, your security deposit will be refunded if you choose not to participate in the Special Stray Vacancy Round of NEET AIQ counseling. According to the Medical Counselling Committee (MCC) guidelines, candidates who do not participate in the Special Stray Vacancy Round or do not get a seat allotted in this round are eligible for a refund of their security deposit.

However, if you are allotted a seat in this round and fail to join or leave it, your security deposit will be forfeited. Ensure you meet all deadlines and follow the MCC rules for refunds.

Hope it helps !

View All

Column I ( Salivary gland)

 

Column II ( Their location)

Parotids

I

Below tongue

Sub-maxillary / sub-mandibular

Ii

Lower jaw

Sub-linguals

Iii

Cheek

Option: 1

a(i), b(ii) , c(iii)

 


Option: 2

a(ii), b(i), c(iii)

 


Option: 3

a(i), b(iii), c(ii)


Option: 4

a(iii), b(ii), c(i)


Ethyl \; ester \xrightarrow[(excess)]{CH_{3}MgBr} P

the product 'P' will be ,

Option: 1


Option: 2


Option: 3

\left ( C_{2}H_{5} \right )_{3} - C- OH


Option: 4


 

    

           

 Valve name                            

             

Function

    I   Aortic valve     A

Prevents blood from going backward from the pulmonary artery to the right ventricle.

    II   Mitral valve     B

 Prevent blood from flowing backward from the right ventricle to the right atrium.

    III   Pulmonic valve     C

 Prevents backward flow from the aorta into the left ventricle.

    IV   Tricuspid valve     D

 Prevent backward flow from the left ventricle to the left atrium.

 

Option: 1

I – A , II – B, III – C, IV – D


Option: 2

 I – B , II – C , III – A , IV – D


Option: 3

 I – C , II – D , III – A , IV – B


Option: 4

 I – D , II – A , III – B , IV – C 

 

 


Column A Column B
A

a) Organisation of cellular contents and further cell growth.  

B

b) Leads to formation of two daughter cells.

C

c) Cell grows physically and increase volume proteins,organells.

D

d)  synthesis and replication of DNA.

Match the correct option as per the process shown in the diagram. 

 

 

 

Option: 1

1-b,2-a,3-d,4-c
 


Option: 2

1-c,2-b,3-a,4-d


Option: 3

1-a,2-d,3-c,4-b

 


Option: 4

1-c,2-d,3-a,4-b


0.014 Kg of N2 gas at 27 0C is kept in a closed vessel. How much heat is required to double the rms speed of the N2 molecules?

Option: 1

3000 cal


Option: 2

2250 cal


Option: 3

2500 cal


Option: 4

3500 cal


0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The modecular weight of the acid will be

Option: 1

32


Option: 2

64


Option: 3

128


Option: 4

256


0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper (in g) which can be deposited will be:

Option: 1

31.75


Option: 2

15.8


Option: 3

47.4


Option: 4

63.5


0.5 g of an organic substance was kjeldahlised and the ammonia released was neutralised by 100 ml 0.1 M HCl. Percentage of nitrogen in the compound is

Option: 1

14


Option: 2

42


Option: 3

28


Option: 4

72


0xone is

Option: 1

\mathrm{KO}_{2}


Option: 2

\mathrm{Na}_{2} \mathrm{O}_{2}


Option: 3

\mathrm{Li}_{2} \mathrm{O}


Option: 4

\mathrm{CaO}


(1) A substance  known as "Smack"

(2) Diacetylmorphine

(3) Possessing a white color

(4) Devoid of any odor

(5) Crystal compound with a bitter taste

(6) Obtained by extracting from the latex of the poppy plant

The above statements/information are correct for:

Option: 1

Morphine


Option: 2

Heroin


Option: 3

Cocaine


Option: 4

Barbiturates


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Veterinary professionals prevent illness by providing vaccines and offering advice on animal nutrition and overall health. Their knowledge extends beyond household animals and includes livestock, wildlife, and exotic animals. Individuals who love animals and want to treat their illnesses, injuries, and diseases must opt for a career as a veterinary doctor.

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A Narcotics Officer is an officer employed by the state to investigate the usage of drugs and their trafficking. A narcotics officer conducts undercover operations, investigates suspected drug dealers, executes raids and other appropriate actions for arresting these traffickers to reduce the circulation of drugs in the country. 

A narcotics officer works in collaboration with other government agencies to stop drug trafficking at borders. He or she engages with various NGOs and public organisations to teach people about the dangerous effects of drug usage. A narcotics officer plays an important role in reducing the illegal activities of drug dealers and the circulation of drugs in the nation.

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A career as R&D Personnel requires researching, planning, and implementing new programs and protocols into their organization and overseeing new products’ development. He or she uses his or her creative abilities to improve the existing products as per the requirements of the target market.

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