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Important Chemistry Formulas For NEET 2025 Exam- Topic-wise Formulas PDF

Important Chemistry Formulas For NEET 2025 Exam- Topic-wise Formulas PDF

Edited By Irshad Anwar | Updated on Jul 22, 2024 12:59 PM IST | #NEET

Important Chemistry Formulas for NEET: Are you preparing for the NEET UG 2025 exam? Are you ready to enter one of India's top medical colleges by passing the National Eligibility and Entrance Test (NEET)? Master the NEET 2025 chemistry formula sheet to score high in the NEET exam. Here, we are providing the NEET chemistry formula sheet pdf 2025, topic-wise, that every NEET aspirant needs to know. From physical chemistry, and organic chemistry to inorganic chemistry, we've got all the chemistry imp formulas for NEET exam preparation. Enhance your NEET preparation and boost your confidence with this chemistry formula sheet for NEET PDF 2024 Continue reading to discover the secrets to cracking NEET Chemistry in 2025.

NTA conducts the NEET Exam once a year. Understanding chemistry concepts such as stoichiometry, thermodynamics, and kinetics requires a solid grasp of equations and reactions and NEET chemistry formulas, which are important components of the NEET exam. NEET aspirants should know that studying important chemistry formulas for NEET and equations during the last-minute revision before an exam matters greatly. In the extremely competitive NEET exam, every mark counts. If students have a solid understanding of the NEET chemistry formula sheet pdf, they can easily secure marks on formula-based questions, which are often simple.

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Finally, mastering these equations and reactions and NEET chemistry important formulas from the Chemistry NEET 2025 formula sheet enhances confidence, accuracy, efficiency, and problem-solving skills. These are necessary qualities for passing the NEET exam. We have compiled a chemistry formula sheet for NEET PDF from the top 11 most-scoring concepts in physics on the NEET syllabus. This formula sheet for the chemistry NEET will guide those preparing for the NEET exam in their last-minute preparation.

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Chemistry Formula Sheet for NEET PDF 2025

  1. Shapes Of Molecules

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The ideal shapes of molecules, which are predicted based on electron pairs and lone pairs of electrons, are mentioned in the table below:

A table is shown that is comprised of six rows and six columns. The header row reads: “Number of Electron Pairs,” “Electron pair geometries; 0 lone pair,” “1 lone pair,” “2 lone pairs,” “3 lone pairs,” and “4 lone pairs.” The first column contains the numbers 2, 3, 4, 5, and 6. The first space in the second column contains a structure in which the letter E is single bonded to the letter X on each side. The angle of the bonds is labeled with a curved, double headed arrow and the value, “180 degrees.” The structure is labeled, “Linear.” The second space in the second column contains a structure in which the letter E is single bonded to the letter X on three sides. The angle between the bonds is labeled with a curved, double headed arrow and the value, “120 degrees.” The structure is labeled, “Trigonal planar.” The third space in the second column contains a structure in which the letter E is single bonded to the letter X four times. The angle between the bonds is labeled with a curved, double headed arrow and the value, “109 degrees.” The structure is labeled, “Tetrahedral.” The fourth space in the second column contains a structure in which the letter E is single bonded to the letter X on five sides. The angle between the bonds is labeled with a curved, double headed arrow and the values “90 and 120 degrees.” The structure is labeled, “Trigonal bipyramid.” The fifth space in the second column contains a structure in which the letter E is single bonded to the letter X on six sides. The angle between the bonds is labeled with a curved, double headed arrow and the value, “90 degrees.” The structure is labeled, “Octahedral.” The first space in the third column is empty while the second contains a structure in which the letter E is single bonded to the letter X on each side and has a lone pair of electrons. The angle between the bonds is labeled with a curved, double headed arrow and the value, “less than 120 degrees.” The structure is labeled, “Bent or angular.” The third space in the third column contains a structure in which the letter E is single bonded to the letter X three times and to a lone pair of electrons. It is labeled with a curved, double headed arrow and the value, “less than 109 degrees.” The structure is labeled, “Trigonal pyramid.” The fourth space in the third column contains a structure in which the letter E is single bonded to the letter X on four sides and has a lone pair of electrons. The bond angle is labeled with a curved, double headed arrow and the values, “less than 90 and less than 120 degrees.” The structure is labeled, “Sawhorse or seesaw.” The fifth space in the third column contains a structure in which the letter E is single bonded to the letter X on five sides and has a lone pair of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “less than 90 degrees.” The structure is labeled, “Square pyramidal.” The first and second spaces in the fourth column are empty while the third contains a structure in which the letter E is single bonded to the letter X on each side and has two lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “less than less than 109 degrees.” The structure is labeled, “Bent or angular.” The fourth space in the fourth column contains a structure in which the letter E is single bonded to the letter X three times and to two lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “less than 90 degrees.” The structure is labeled, “T - shape.” The fifth space in the fourth column contains a structure in which the letter E is single bonded to the letter X on four sides and has two lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value “90 degrees.” The structure is labeled, “Square planar.” The first, second and third spaces in the fifth column are empty while the fourth contains a structure in which the letter E is single bonded to the letter X on each side and has three lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “180 degrees.” The structure is labeled, “Linear.” The fifth space in the fifth column contains a structure in which the letter E is single bonded to the letter X three times and to three lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value, “less than 90 degrees.” The structure is labeled, “T - shape.” The first, second, third, and fourth spaces in the sixth column are empty while the fifth contains a structure in which the letter E is single bonded to the letter X on each side and has four lone pairs of electrons. The bond angle is labeled with a curved, double headed arrow and the value “180 degrees.” The structure is labeled, “Linear.” All the structures use wedges and dashes to give them three dimensional appearances.

  1. Solubility And Solubility Products

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General Representation
\mathrm{A_xB_y} \rightleftharpoons \mathrm{xA}^{+y}+\mathrm{yB}^{-\mathrm{x}}

\mathrm{Ksp =[ A^{+y}]^x \times[ B^{-x}]^y}

Relation between Solubility(s) and Solubility Product (Ksp)
\mathrm{A_xB_y} \rightleftharpoons \mathrm{xA}^{+y}+\mathrm{yB}^{-\mathrm{x}} s 0 0 - xs ys
\text { Thus, } \mathrm{Ksp = x ^{x} y ^{y}( s )^{ x + y }}

The Gas Laws- Boyle’s Law (Pressure-Volume Relationship) -

Also read:

  1. The Gas Laws- Boyle’s Law (Pressure - Volume Relationship)

    1714400387682

k1 is the proportionality constant whose value depends upon the following factors.

1714400387851 1714400387927


Relation between Density and Pressure

1714400388217

  1. Mathematical Analysis of Cubic System

Coordination Number (C. No.)

In Simple Cubic (SC): 6

In Face Centered Cubic (FCC): 12

In Body Centered Cubic (BCC): 8

Density of Lattice Matter (d)

It is the ratio of mass per unit cell to the total volume of a unit cell and it is found out as follows.

\mathrm{d}=\frac{\mathrm{Z} \times \text { Atomic weight }}{\mathrm{N}_{0} \times \text { Volume of unit cell }\left(\mathrm{a}^{3}\right)}


Here, d = Density

Z = Number of atoms

N0 = Avogadro number

a3 = Volume

a = Edge length

To find the density of a unit cell in cm3, m must be taken in g/mole and should be in cm.

Radius Ratio

It is the ratio of the radius of an octahedral void to the radius of the sphere forming the close-packed arrangement Normally, ionic solids are more compact, as voids are also occupied by cation (smaller in size). The pattern of arrangements and type of voids both depend on the relative size (ionic size) of two ions in a solid.

For example, when r+ = r- the most probable and favourable arrangement is BCC type.

With the help of relative ionic radii, it is easier to predict the most probable arrangement. This property is expressed as radio ratio.

\mathrm{\text { Radius ratio }=\frac{r^{+} \text {(radius of cation) }}{r^{-} \text { (Radius of anion) }}}


From the value of the radius ratio, it is clear that the larger the radius ratio, the larger the size of the cation, and the more anions needed to surround it—that is, the more coordination numbers.

Radius ratio for tetrahedron

\begin{array}{l}{\text { Angle } A B C \text { is the tetrahedral angle of } 109.5^{\circ}} \\\\ {\angle A B D=\frac{109.5}{2}=5475^{\circ}} \\\\ {\text { In triangle } A B D} \\\\ {\text { Sin } A B D=0.8164=A D / A B} \\\\ {\text { or } \frac{r^{*}+r}{r}=\frac{1}{0.8164}=1.225} \\\\ {\text { or } \frac{r^{*}}{\Gamma}=0.225}\end{array}

1714400387372

Radius ratio for octahedron

\begin{array}{l}{\mathrm{AB}=\mathrm{r}^{+}+\mathrm{r}} \\\\ {\mathrm{BD}=\mathrm{r}} \\\\ {\angle \mathrm{ABC}=45^{\circ}} \\\\ {\text { In triangle } \mathrm{ABD}}\end{array}\\\\\\\begin{array}{l}{\operatorname{Cos} A B D=0.7071=B D / A B} \\\\ {=\frac{r}{r^{+}+r}} \\\\ {\text { or } \frac{r^{+}+r}{r}=\frac{1}{0.707}=1.414} \\\\ {\text { or } \frac{r}{r^{4}}=0.414}\end{array}


1714400388353

  1. Charge On Colloids

Colloidal particles always carry an electric charge. The nature of this charge is the same for all the particles in a given colloidal solution and may be either positive or negative.

  1. Oxidation State

An interesting feature in the variability of oxidation states of the d-block elements is noticed among the groups. Although in the p–block the lower oxidation states are favoured by the heavier members (due to the inert pair effect), the opposite is true in the groups of d-block.

Also read:

  1. Preparation Of Aldehyde

Rosenmund Reduction

1714400387289

Stephen Reduction
1714400387587

  1. Nucleophilic Addition Reaction:

(i) Mechanism of nucleophilic addition reactions:
1714400386979

1714400387462

  1. Reduction And Oxidation Reaction

Reduction to hydrocarbons:
The carbonyl group of aldehydes and ketones is reduced to the CH2 group on treatment with zinc amalgam and concentrated hydrochloric acid (Clemmensen reduction) hydrazine hydrazone or with hydrazine, followed by heating with sodium or potassium hydroxide in a high boiling solvent such as ethylene glycol (Wolff-Kishner reduction).

Oxidation
Aldehydes differ from ketones in their oxidation reactions. Aldehydes are easily oxidised to carboxylic acids on treatment with common oxidising agents like nitric acid, potassium permanganate, potassium dichromate, etc. Even mild oxidising agents, mainly Tollens’ reagent and Fehlings’ reagent, also oxidise aldehydes.

  1. Chemical Properties Of Carboxylic Acid:

Formation of Anhydride

1714400388411

Reaction with Ammonia
1714400388275

Reduction

1714400388475

Decarboxylation
1714400388616

Kolbe's electrolysis
1714400389110 Halogenation 1714400388672

Ring substitution
1714400389018

1714400388545

  1. Carbohydrates

Carbohydrates -

These are polyhydroxy aldehydes, ketones or substances that form these on hydrolysis and possess at least one chiral atom. The (-OH) group is available in the form of hemiacetals or hemiketals.

Classification:

Carbohydrates can be classified into three categories:

  1. Monosaccharides: They are the simplest carbohydrates which cannot be hydrolysed into smaller molecules. They are sweet and crystalline and are called sugars.

  2. Oligosaccharides: These carbohydrates, on hydrolysis, give two to nine molecules of monosaccharides classified as di-, tri, tetra-saccharides, etc. For example, sucrose, maltose, lactose, raffinose, etc. They are also called sugars.

  3. Polysaccharides: These carbohydrates, on hydrolysis, give a large number of monosaccharides, e.g., starch, cellulose, etc. They are also called non-sugars.

Reducing and Non-reducing Sugars
Those sugars which reduce Fehling's and Tollens's solutions are called reducing sugars and those which do not reduce these reagents are called non-reducing sugars.

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Questions related to NEET

Have a question related to NEET ?

Hello Dharmik,

With a NEET 2024 score of 538 and an All India Rank of 153,336, you have a chance to secure an MBBS seat, especially under the state quota. Here’s a breakdown of your options:

Key Points:

  • State Quota : 85% of seats in state medical colleges are reserved for state quota. Your chances are better here compared to the All India Quota (AIQ).

  • Reserved Category : If you belong to a reserved category (OBC, SC, ST), your chances improve due to lower cutoff requirements.

    GMERS (Gujarat Medical Education and Research Society):

  • State Quota : Your score might be competitive enough for a seat in GMERS under the state quota.

  • Previous Cutoffs : Check the previous years’ cutoffs for GMERS colleges to get a better idea.

    Government Medical Colleges:

  • All India Quota : Admission under AIQ can be tough with this rank, but it’s worth applying and participating in counseling.

  • State Government Colleges : Look into government colleges in your home state, as cutoffs can vary widely.

    If you want to get a list of all the possible colleges that you can get at your rank then,

    I would recommend you to use NEET college predictor tool by Careers360 to get the list of possible colleges you can get with your rank.


    Here is the link to the tool:

    https://medicine.careers360.com/neet-college-predictor?utm_source=qna&utm_medium=neet_cp

    Click on the above link, fill the required details and you will get the list of possible colleges at your rank.


    I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

    Thank you and wishing you all the best for your bright future.

Hello student

With a NEET score of 256, you may be eligible for admission to private medical colleges in Uttar Pradesh . Here are some points to consider:


- *Private Medical Colleges*: All private medical colleges in Uttar Pradesh have one type of cutoff .

- *100% All India Management Quota Cutoff*: The Directorate of Medical Education and Training (DMET), Lucknow, releases the Uttar Pradesh MBBS Management Quota Cutoff college-wise and category-wise .

- *No NRI seats*: There are no NRI seats available in Uttar Pradesh .

- *Cutoff Ranks and Scores*: The cutoff ranks and scores vary for different categories and colleges .

- *Eligibility*: You may be eligible for admission to private medical colleges with a NEET score of 256, but the eligibility criteria may vary for each college .


Some examples of private medical colleges in Uttar Pradesh and their cutoff scores are :


- *Autonomous State Medical College, Ghazipur*: 612 (OPEN category)

- *MAHARANI LAXMI BAI MEDICAL COLL, JHANSI*: 610 (OBC category)

- *Autonomous State Medical College Society, Mirzapur*: 610 (EWS category)

- *Govt Medical College Basti*: 485 (SC category)

- *Autonomous State Medical College, Pratapgarh*: 449 (ST category)


Please note that these cutoff scores are subject to change and may vary for the current academic year. It's always best to check with the colleges directly for the most up-to-date information.

Hello student

Congratulations on your NEET 2024 score! With a rank of 71659 and a score of 605 marks in the GEN category with no reservation, your chances of getting a government BDS seat are possible, but it depends on various factors:


1. *Cutoff ranks*: Last year's cutoff ranks for government BDS seats varied across India, ranging from 30,000 to 1,50,000.

2. *Seat matrix*: The number of BDS seats available in government colleges and their distribution across states.

3. *State-wise counseling*: Counseling processes and seat allotment vary across states.

4. *Category-wise cutoffs*: GEN category cutoffs might be higher than reserved categories.


Based on previous years' trends, here are some possible scenarios:


- *Kerala*: You might get a government BDS seat in Kerala, as their cutoff ranks have been around 70,000-80,000 in previous years.

- *Tamil Nadu*: You have a chance in Tamil Nadu, where cutoff ranks have been around 60,000-70,000.

- *Other states*: In states like Maharashtra, Gujarat, or Rajasthan, the competition is higher, and cutoff ranks might be lower (around 40,000-50,000).


To increase your chances:


1. *Participate in state-wise counseling*: Register for counseling in multiple states to explore opportunities.

2. *Check seat matrices*: Look for states with a higher number of BDS seats in government colleges.

3. *Stay updated*: Monitor counseling schedules, cutoffs, and seat allotment lists regularly.


Remember, these are general insights based on previous years' trends. The actual cutoffs and seat allotment may vary. Best of luck!

Hello aspirant,
The competition for medical seats, especially in private colleges, is extremely intense. Cutoff marks have been rising steadily over the years. To get a seat in a private medical college, you would generally need a score significantly higher than 425.
But, you should not lose hope here, instead, you can consider other healthcare-related fields like BDS, BAMS, BHMS, or paramedical courses. If you're determined to pursue MBBS, focus on improving your score for the next NEET exam.
Remember, it's essential to stay positive and explore alternative paths.

I hope this information helps you.

Hello aspirant,
While the exact cutoff for BAMS in CSMSS can fluctuate yearly based on various factors, a score of 478 is generally considered good for getting admission to a government Ayurveda college like CSMSS.
Factors Affecting Admission:

  • Category: If you belong to a reserved category (SC, ST, OBC), your chances of getting a seat increase significantly.
  • State Quota: Competition is generally lower for state quota seats compared to All India Quota seats.
  • Counseling Process: Your final rank after the counseling process will determine your admission.

    To increase your chances, you can participate in counselling or you can also explore other options too.

    I hope this information helps.
View All

Column I ( Salivary gland)

 

Column II ( Their location)

Parotids

I

Below tongue

Sub-maxillary / sub-mandibular

Ii

Lower jaw

Sub-linguals

Iii

Cheek

Option: 1

a(i), b(ii) , c(iii)

 


Option: 2

a(ii), b(i), c(iii)

 


Option: 3

a(i), b(iii), c(ii)


Option: 4

a(iii), b(ii), c(i)


Ethyl \; ester \xrightarrow[(excess)]{CH_{3}MgBr} P

the product 'P' will be ,

Option: 1


Option: 2


Option: 3

\left ( C_{2}H_{5} \right )_{3} - C- OH


Option: 4


 

    

           

 Valve name                            

             

Function

    I   Aortic valve     A

Prevents blood from going backward from the pulmonary artery to the right ventricle.

    II   Mitral valve     B

 Prevent blood from flowing backward from the right ventricle to the right atrium.

    III   Pulmonic valve     C

 Prevents backward flow from the aorta into the left ventricle.

    IV   Tricuspid valve     D

 Prevent backward flow from the left ventricle to the left atrium.

 

Option: 1

I – A , II – B, III – C, IV – D


Option: 2

 I – B , II – C , III – A , IV – D


Option: 3

 I – C , II – D , III – A , IV – B


Option: 4

 I – D , II – A , III – B , IV – C 

 

 


Column A Column B
A

a) Organisation of cellular contents and further cell growth.  

B

b) Leads to formation of two daughter cells.

C

c) Cell grows physically and increase volume proteins,organells.

D

d)  synthesis and replication of DNA.

Match the correct option as per the process shown in the diagram. 

 

 

 

Option: 1

1-b,2-a,3-d,4-c
 


Option: 2

1-c,2-b,3-a,4-d


Option: 3

1-a,2-d,3-c,4-b

 


Option: 4

1-c,2-d,3-a,4-b


0.014 Kg of N2 gas at 27 0C is kept in a closed vessel. How much heat is required to double the rms speed of the N2 molecules?

Option: 1

3000 cal


Option: 2

2250 cal


Option: 3

2500 cal


Option: 4

3500 cal


0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The modecular weight of the acid will be

Option: 1

32


Option: 2

64


Option: 3

128


Option: 4

256


0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper (in g) which can be deposited will be:

Option: 1

31.75


Option: 2

15.8


Option: 3

47.4


Option: 4

63.5


0.5 g of an organic substance was kjeldahlised and the ammonia released was neutralised by 100 ml 0.1 M HCl. Percentage of nitrogen in the compound is

Option: 1

14


Option: 2

42


Option: 3

28


Option: 4

72


0xone is

Option: 1

\mathrm{KO}_{2}


Option: 2

\mathrm{Na}_{2} \mathrm{O}_{2}


Option: 3

\mathrm{Li}_{2} \mathrm{O}


Option: 4

\mathrm{CaO}


(1) A substance  known as "Smack"

(2) Diacetylmorphine

(3) Possessing a white color

(4) Devoid of any odor

(5) Crystal compound with a bitter taste

(6) Obtained by extracting from the latex of the poppy plant

The above statements/information are correct for:

Option: 1

Morphine


Option: 2

Heroin


Option: 3

Cocaine


Option: 4

Barbiturates


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