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The chapter d- and f-block elements from class 12 chemistry are included in the NEET syllabus. The d and f block elements have 6% weightage in NEET Chemistry. The d- and f- block elements show unique properties that are important for understanding chemical reactions. Students can continue reading this article to gain a complete overview of the d and f block elements NEET PYQ. Attempting previous year questions boosts confidence and improves understanding.
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To complete the NEET Chemistry syllabus within time, students can start with the d and f block elements. These elements are also known as transition and inner transition metals. Qualifying for the NEET exam needs a well-structured and systematic approach. Solving the NEET d and f block elements' previous years' questions makes students familiar with the question level. This is one of the best NEET preparation tips to secure a high rank.
In the NEET exam, NTA mainly asks concept-based questions. So, before solving the NEET d and f block elements previous year questions, it is important to know the basics. Students can refer to the NCERT books for NEET to build a strong foundation. Apart from that, there are two main points to know the basics of d and f block elements. These points are mentioned below:
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The electronic configuration of any element is like its fingerprint. It shows how the electrons are arranged in a definite manner. For d-block elements, the general configuration is (N-1) d1-10 ns(0 - 2)
The d-block elements exhibit variable oxidation states. They form coloured ions and show catalytic properties.
The d-block elements have an incomplete d-subshell in their neutral atom or ions. Their general electronic configuration is (n - 1)d. Transition elements show variable oxidation states and exhibit catalytic properties. D-block elements are also good conductors of heat and electricity.
The f-block elements are also known as inner transition elements. The general electronic configuration of F block elements is (n - 2) f.
Lanthanoids – show electronic configuration, variable oxidation states, and lanthanoid contraction.
Actinoids – show electronic configuration and variable oxidation states.
The d and f-block elements form various complex compounds with other elements. Students can make a NEET preparation timetable to solve the d and f block elements questions. Analysing the NEET chemistry chapter-wise weightage helps in focusing on the scoring chapter first. Given below is a table of the number of NEET d and f block elements previous year's questions.
| Year | No. of Questions |
|---|---|
2025 | 1 |
2024 | 3 |
2023 | 2 |
2022 | 2 |
2021 | 2 |
2020 | 2 |
Accessing the PDF of the previous year's questions can help aspirants a lot. Students who don’t want to waste time searching for d and f block elements, NEET PYQ are at the right place. Careers360 has provided the PDF, which can be accessed easily without the internet. Solving these, along with the NEET question papers, can increase the scores to a large extent.
| Particulars | PDF Link |
|---|---|
d and f-Bock Elements Previous Year Questions PDF |
According to toppers, the best way to clear the NEET exam is to practice the PYQs. Students have to solve the NEET 2024 question paper to know what type of questions are asked in this unit. Given below are a few NEET d and f block elements previous year questions. Aspirants can make a sheet of important NEET chemistry formulas to solve the questions with accuracy.
Question 1: Given below are two statements :
Statement I: Ferromagnetism is considered an extreme form of paramagnetism.
Statement II: The number of unpaired electrons in a $\mathrm{Cr}^{2+}$ ion $(\mathrm{Z} \subseteq 24)$ is the same as that of a Nd ${ }^{3+}$ ion $(\mathrm{Z}=60)$.
In light of the above statements, choose the correct answer from the options given below :(NEET 2025)
Options
Statement I is false, but Statement II is true
Both Statement I and Statement II are true
Both Statement I and Statement II are false
Statement I is true, but Statement II is false
Answer: Ferromagnetism is considered an extreme form of paramagnetism. This is a true statement.
Unpaired electrons in $\mathrm{Cr}^{2+}$ and $\mathrm{Nd}^{3+}$ .
- $\mathrm{Cr}^{2+}:[\mathrm{Ar}] 3 \mathrm{~d}^4 \rightarrow 4$ unpaired electrons
- $\mathrm{Nd}^{3+}:[\mathrm{Xe}] 4 \mathrm{f}^3 \rightarrow 3$ unpaired electrons
So they do not have the same number of unpaired electrons.
Hence, the correct answer is option (4), Statement I is true, but Statement II is false.
Question 2: Among $\mathrm{VO}_2^{+}, \mathrm{MnO}_4^{-}$and $\mathrm{Cr}_2 \mathrm{O}_7^{2-}$, the spin-only magnetic moment value of the species with the least oxidising ability is..................BM (Nearest integer).
(Given atomic member $\mathrm{V}=23, \mathrm{Mn}=25, \mathrm{Cr}=24)$: (NEET 2024)
Options
0
1
2
3
Answer:
For 3d transition series;
Oxidising power: $\mathrm{V}^{+5}<\mathrm{Cr}^{+6}<\mathrm{Mn}^{+7}$
$\mathrm{V}^{+5}:[\operatorname{Ar}] 4 \mathrm{~s}^0 3 \mathrm{~d}^0$
Number of unpaired electrons =0
$\mu=0$
Hence, the correct answer is option (1), 0.
Question 3: The stability of Cu2+ is more than Cu+ salts in aqueous solution due to: (NEET 2023)
Options
first ionisation enthalpy
enthalpy of atomization
hydration energy
second ionisation enthalpy
Answer: The stability of Cu2+ is more than Cu+ salts in an aqueous solution due to hydration energy.
Hence, the correct answer is option (3), hydration energy.
Question 4: In the neutral or faintly alkaline medium, KMnO4 oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from: (NEET 2022)
Options
+6 to +4
+7 to +3
+6 to +5
+7 to +4
Answer:
In a neutral or faintly alkaline medium $KMnO_4$ is converted to $MnO_2$.
$MnO_4^- \;\;\rightarrow\;\; MnO_2$
$(+7) \;\;\;\;\; (+4)$
Hence, the correct answer is option (4). +7 to +4
Question 5: Zr(Z=40) and Hf(Z=72) have similar atomic and ionic radii because of: (NEET 2021)
Options
Belonging to the same group
Diagonal relationship
Lanthanoid contraction
Having Similar chemical properties
Answer: Zr and Hf have almost the same size. This is because of the Lanthanoid contraction.
Hence, the correct answer is option (3), Lanthanoid contraction.
Having an understanding of important topics gives preparation the right direction. Candidates are advised to study from the best NEET chemistry books to know the basics. After that, it becomes easy to solve the d and f block elements questions in NEET. Students thinking of how to study chemistry for NEET can use a systematic approach. Given below is a table of topics that are covered in the d and f block elements NEET PYQ.
| Topic | Details |
|---|---|
Electronic Configurations | Understand the filling of (n-1)d orbitals and exceptions like Cr and Cu. |
General Properties of Transition Elements | Metallic character, ionization enthalpy, melting and boiling points, oxidation states, colour, magnetic properties, catalytic properties, alloy formation, and complex formation. |
Lanthanides and Actinides | Electronic configurations, oxidation states, lanthanide contraction, and uses. |
Important Compounds | Preparation, properties, and uses of
|
On Question asked by student community
Hello,
Here are the important naming reactions for the NEET preparation.
Naming Reaction for NEET Preparation
Hope it helps your preparation. Good luck.
Hi
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Thank you.
Hello
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If your aim is strictly government MBBS, a reattempt next year can increase your chances a lot.
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Hope this information will help you.
Hello aspirant,
For NEET, you must select your central government category, not the state category. Jaat from Uttar Pradesh is counted as General in the central list because this caste is not included in the Central OBC list. Even though you may fall under OBC at the state level, NEET uses only the central list for reservation. So, in the NEET application, you should fill General category to avoid any issues during counselling or document verification.
FOR REFERENCE : https://medicine.careers360.com/articles/neet-eligibility-criteria
THANK YOU
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Here you can access Subject Wise High Scoring Topics for NEET 2026:
Biology
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