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It is possible to secure 150+ marks in NEET Physics by adopting a proper study strategy and regular practice. NEET Physics Questions To Score 150+ Marks Top 100 are prepared from past years’ NEET question papers and include concepts, formulae, and problems which are repeatedly asked in the NEET exam. Although the same questions do not appear in the paper, the same concept appears in a new format, and hence such questions are useful for NEET 2027 preparation.
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The set of 100 important NEET Physics questions with answers will enable you to strengthen the understanding of concepts, improve your calculation speed, and learn the important chapters. Solving these important Physics questions on a regular basis will help you identify your strengths and weaknesses, gain confidence, and be accurate in your calculations. Irrespective of whether your target score in NEET 2027 is 600+, 650+ or 700+; solving these well-selected questions along with NCERT book reading and previous year question papers will definitely help you in securing good marks in NEET Physics
The Top 100 Questions in NEET Physics PDF is an important resource for those students who are preparing for NEET 2027. After carefully analysing the question paper from past years, the important chapters, important NEET physics formulas, concept based questions, and numericals of exam level which have been repeatedly asked in NEET have been covered in this PDF.
These Top 100 NEET Physics Questions and Answers are aimed at improving the conceptual clarity, numerical ability, speed, and accuracy of students. Instead of solving random questions, aspirants can study the concepts which have repeatedly appeared in NEET in the past.
Make sure that these questions are included in your revision plan besides the NCERT, chapter-wise previous years' questions, and mocks. With regular practice, you will be able to rectify your weaknesses, reduce calculation errors, and get acquainted with the level and pattern of questions asked in NEET. If your aim is to score 150+ marks in NEET Physics, this important resource can play an important role in your NEET 2027 preparation.
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Top 100 NEET Physics Questions PDF |
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The NEET Physics most asked questions are based on repeated concepts and previous year trends. Practising these important NEET Physics questions 2027 helps improve accuracy, speed, and understanding of exam patterns.
Solve these top NEET Physics questions with solutions to strengthen concepts and increase your chances of scoring 150+ marks.
Q1. The current passing through the battery in the given circuit is:

(a) 1.5 A
(b) 2.0 A
(c) 0.5 A
(d) 2.5 A
Correct answer: (c) 0.5 A
Explanation:
Between points $B$ and $D$, there are two parallel paths.
For path $B-C-D$, resistance $=2.5,\Omega+1.5,\Omega=4,\Omega$.
For path $B-E-D$, resistance $=6,\Omega+1.5,\Omega=7.5,\Omega$.
$\frac{1}{R}=\frac{1}{4}+\frac{1}{7.5}=\frac{11.5}{30}$
$R=\frac{30}{11.5}\approx2.61,\Omega$
$R_{total}=5,\Omega+2.61,\Omega+0.33,\Omega+3,\Omega\approx10,\Omega$
$I=\frac{V}{R}=\frac{5}{10}=0.5,A$
Q2. An electron moving with speed $v=\frac{c}{100}$ enters a magnetic field $B=9 \times 10^{-2} T$ perpendicular to its motion. What electric field must be applied so that the electron moves undeflected?
(a) $\vec{E} | \vec{B}, E=27 \times 10^2 V/m$
(b) $\vec{E} \perp \vec{B}, E=27 \times 10^4 V/m$
(c) $\vec{E} | \vec{B}, E=27 \times 10^4 V/m$
(d) $\vec{E} \perp \vec{B}, E=27 \times 10^2 V/m$
Correct answer: (b) $\vec{E} \perp \vec{B}, E=27 \times 10^4 V/m$
Explanation:
For no deflection:
$qE=qvB$
$\Rightarrow E=vB$
$v=\frac{3 \times 10^8}{100}=3 \times 10^6 m/s$
$E=(3 \times 10^6)(9 \times 10^{-2})=27 \times 10^4 V/m$
The electric field must be perpendicular to $\vec{B}$.
Q3. In a certain camera, a combination of four similar thin convex lenses is arranged axially in contact. Then the power of the combination and the total magnification in comparison to the power and magnification for each lens will be, respectively.
(a) $p, m^4$
(b) $4p, m^4$
(c) $4p, 4m$
(d) $p, 4m$
Correct answer: (b) $4p, m^4$
Explanation:
For lenses placed in contact, powers add algebraically:
$P_{total}=p+p+p+p=4p$
Magnification of lenses in contact is the product of individual magnifications:
$M_{total}=m \times m \times m \times m=m^4$
Q4. Two identical charged conducting spheres $A$ and $B$ have their centres separated by a certain distance. The charge on each sphere is $q$, and the force of repulsion between them is $F$. A third identical uncharged conducting sphere is brought in contact first with sphere $A$ and then with $B$, and finally removed. The new force of repulsion between spheres $A$ and $B$ is:
(a) $\frac{F}{2}$
(b) $\frac{F}{3}$
(c) $\frac{3F}{8}$
(d) $\frac{F}{4}$
Correct answer: (c) $\frac{3F}{8}$
Explanation:
Initial force is
$F=\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{r^2}$
After contact with $A$, the charge on each becomes $\frac{q}{2}$
After contact with $B$, total charge is
$q+\frac{q}{2}=\frac{3q}{2}$
So final charges are
$A=\frac{q}{2}, \quad B=\frac{3q}{4}$
A new force is
$F'=\frac{1}{4 \pi \varepsilon_0} \frac{\left(\frac{q}{2}\right)\left(\frac{3q}{4}\right)}{r^2}=\frac{3}{8}F$
Q5. A bob of heavy mass is suspended by a light string of length $l$. The bob is given a horizontal velocity $v_0$. If the string gets slack at some point, making an angle $\theta$ from the horizontal, the ratio of the speed of the bob at that point to its initial speed is

(a) $\left(\frac{\sin \theta}{2+3 \sin \theta}\right)^{1/2}$
(b) $(\sin \theta)^{1/2}$
(c) $\left(\frac{1}{2+3 \sin \theta}\right)^{1/2}$
(d) $\left(\frac{\cos \theta}{2+3 \sin \theta}\right)^{1/2}$
Correct answer: (d) $\left(\frac{\cos \theta}{2+3 \sin \theta}\right)^{1/2}$
Explanation:
Using energy conservation,
$v_0^2=v^2+2gl(1-\cos \theta)$
At slack condition,
$\frac{mv^2}{l}=mg \cos \theta \Rightarrow v^2=gl \cos \theta$
Substituting,
$v_0^2=gl(2+3 \sin \theta)$
So,
$\frac{v^2}{v_0^2}=\frac{\cos \theta}{2+3 \sin \theta}$
Practising the Top 100 NEET Physics Questions 2027 helps you focus on high-weightage topics, improve accuracy, and boost your chances of scoring 150+ marks.
Covers the most important NEET Physics concepts and formulas
Focuses on NEET physics high-weightage chapters and frequently asked questions
Improves concept clarity and strengthens NCERT basics
Helps understand the NEET exam pattern and question trends
Increases speed, accuracy, and problem-solving skills
Reduces calculation errors and negative marking
Helps identify weak areas for better NEET preparation
Builds confidence for the actual exam
Boosts chances of scoring 150+ marks in NEET Physics
Top 100 questions in NEET Physics have been chosen after analysing previous year’s NEET papers to pick out those concepts which are always asked in NEET. Rather than choosing questions at random, the top 100 questions focus on consistent themes, high-weightage chapters and numerical questions based on the pattern of NEET.
Top 100 questions in NEET Physics have been picked out according to the following criteria:
Frequently Asked Questions (FAQs)
Yes, these Top 100 NEET Physics questions cover high-weightage topics, but you should also revise concepts and practise mock tests for best results.
These questions are selected from previous year NEET papers, repeated concepts, and important formulas based on exam trends.
Solve these questions daily, revise formulas, and analyse mistakes to improve accuracy, speed, and problem-solving skills.
On Question asked by student community
Dear Student,
Please refer to the link provided below for the NEET 2025 Question Paper:
https://medicine.careers360.com/articles/neet-2025-question-paper-with-solutions
If you need any other resource, do let us know.
Hello,
Arihant’s Question Bank is a good option for NEET preparation, especially for practising chapter-wise and exam-oriented questions. It can be used along with NCERT, previous-year questions (PYQs), and mock tests for more effective preparation.
You can check the high-weightage NEET exam physics chapter from the links given below:
https://medicine.careers360.com/articles/neet-physics-chapter-wise-weightage
https://medicine.careers360.com/articles/neet-physics-important-questions
Private or deemed MBBS under Rs 60 lakh total tuition fee is also difficult, but some private colleges in lower fee states or management quota may be worth checking during later counselling rounds or stray vacancy. Deemed universities generally exceed Rs 60 lakh for the full MBBS course, so they
Hey there,
NEET PG stands for National Eligibility cum Entrance Test – Postgraduate.
It is the entrance examination for admission to MD, MS and PG Diploma medical courses in India.
Thanks and all the best,
Nischal
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