Top 100 Questions in NEET Physics to Score 150+ Marks

Top 100 Questions in NEET Physics PDF to Score 150+ Marks

The NEET Physics Top 100 Questions PDF 2026 is carefully prepared after analysing previous year question papers and high-weightage topics. These questions are selected based on frequently asked concepts, important NEET physics formulas, and exam trends. Practising these most expected NEET Physics questions helps you focus on scoring areas instead of wasting time on less relevant topics.

This Top 100 NEET Physics questions list is made to strengthen your concepts, improve problem-solving speed, and improve accuracy. You can include these questions in your daily study plan to build a strong NEET 2026 preparation strategy.

Regular practice of these important Physics questions for NEET 2026 will help you understand question patterns, reduce calculation errors, and boost confidence. If your goal is to score 150+ marks in NEET Physics, this targeted practice approach will significantly improve your performance.

NEET Physics Most Asked Questions to Score 150+ Marks

The NEET Physics most asked questions are based on repeated concepts and previous year trends. Practising these important NEET Physics questions 2026 helps improve accuracy, speed, and understanding of exam patterns.

Solve these top NEET Physics questions with solutions to strengthen concepts and increase your chances of scoring 150+ marks.

Q1. The current passing through the battery in the given circuit is:

(a) 1.5 A

(b) 2.0 A

(c) 0.5 A

(d) 2.5 A

Correct answer: (c) 0.5 A

Explanation:

Between points $B$ and $D$, there are two parallel paths.

For path $B-C-D$, resistance $=2.5,\Omega+1.5,\Omega=4,\Omega$.

For path $B-E-D$, resistance $=6,\Omega+1.5,\Omega=7.5,\Omega$.

$\frac{1}{R}=\frac{1}{4}+\frac{1}{7.5}=\frac{11.5}{30}$

$R=\frac{30}{11.5}\approx2.61,\Omega$

$R_{total}=5,\Omega+2.61,\Omega+0.33,\Omega+3,\Omega\approx10,\Omega$

$I=\frac{V}{R}=\frac{5}{10}=0.5,A$

Q2. An electron moving with speed $v=\frac{c}{100}$ enters a magnetic field $B=9 \times 10^{-2} T$ perpendicular to its motion. What electric field must be applied so that the electron moves undeflected?

(a) $\vec{E} | \vec{B}, E=27 \times 10^2 V/m$

(b) $\vec{E} \perp \vec{B}, E=27 \times 10^4 V/m$

(c) $\vec{E} | \vec{B}, E=27 \times 10^4 V/m$

(d) $\vec{E} \perp \vec{B}, E=27 \times 10^2 V/m$

Correct answer: (b) $\vec{E} \perp \vec{B}, E=27 \times 10^4 V/m$

Explanation:

For no deflection:

$qE=qvB$

$\Rightarrow E=vB$

$v=\frac{3 \times 10^8}{100}=3 \times 10^6 m/s$

$E=(3 \times 10^6)(9 \times 10^{-2})=27 \times 10^4 V/m$

The electric field must be perpendicular to $\vec{B}$.

Q3. In a certain camera, a combination of four similar thin convex lenses is arranged axially in contact. Then the power of the combination and the total magnification in comparison to the power and magnification for each lens will be, respectively.

(a) $p, m^4$
(b) $4p, m^4$
(c) $4p, 4m$
(d) $p, 4m$

Correct answer: (b) $4p, m^4$

Explanation:
For lenses placed in contact, powers add algebraically:
$P_{total}=p+p+p+p=4p$
Magnification of lenses in contact is the product of individual magnifications:
$M_{total}=m \times m \times m \times m=m^4$

Q4. Two identical charged conducting spheres $A$ and $B$ have their centres separated by a certain distance. The charge on each sphere is $q$, and the force of repulsion between them is $F$. A third identical uncharged conducting sphere is brought in contact first with sphere $A$ and then with $B$, and finally removed. The new force of repulsion between spheres $A$ and $B$ is:

(a) $\frac{F}{2}$
(b) $\frac{F}{3}$
(c) $\frac{3F}{8}$
(d) $\frac{F}{4}$

Correct answer: (c) $\frac{3F}{8}$

Explanation:
Initial force is
$F=\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{r^2}$
After contact with $A$, the charge on each becomes $\frac{q}{2}$
After contact with $B$, total charge is
$q+\frac{q}{2}=\frac{3q}{2}$
So final charges are
$A=\frac{q}{2}, \quad B=\frac{3q}{4}$
A new force is
$F'=\frac{1}{4 \pi \varepsilon_0} \frac{\left(\frac{q}{2}\right)\left(\frac{3q}{4}\right)}{r^2}=\frac{3}{8}F$

Q5. A bob of heavy mass is suspended by a light string of length $l$. The bob is given a horizontal velocity $v_0$. If the string gets slack at some point, making an angle $\theta$ from the horizontal, the ratio of the speed of the bob at that point to its initial speed is

(a) $\left(\frac{\sin \theta}{2+3 \sin \theta}\right)^{1/2}$
(b) $(\sin \theta)^{1/2}$
(c) $\left(\frac{1}{2+3 \sin \theta}\right)^{1/2}$
(d) $\left(\frac{\cos \theta}{2+3 \sin \theta}\right)^{1/2}$

Correct answer: (d) $\left(\frac{\cos \theta}{2+3 \sin \theta}\right)^{1/2}$

Explanation:

Using energy conservation,

$v_0^2=v^2+2gl(1-\cos \theta)$

At slack condition,

$\frac{mv^2}{l}=mg \cos \theta \Rightarrow v^2=gl \cos \theta$

Substituting,

$v_0^2=gl(2+3 \sin \theta)$

So,

$\frac{v^2}{v_0^2}=\frac{\cos \theta}{2+3 \sin \theta}$

Why You Should Practice the Top 100 NEET 2026 Physics Questions?

Practising the Top 100 NEET Physics Questions 2026 helps you focus on high-weightage topics, improve accuracy, and boost your chances of scoring 150+ marks.

• Covers the most important NEET Physics concepts and formulas

• Focuses on NEET physics high-weightage chapters and frequently asked questions

• Improves concept clarity and strengthens NCERT basics

• Helps understand the NEET exam pattern and question trends

• Increases speed, accuracy, and problem-solving skills

• Reduces calculation errors and negative marking

• Helps identify weak areas for better NEET preparation

• Builds confidence for the actual exam

• Boosts chances of scoring 150+ marks in NEET Physics

NEET 2026 Physics: Top 100 Questions Selection Method

The Top 100 NEET Physics Questions 2026 are selected using a smart and exam-focused approach based on previous year trends and high-weightage topics.

• Based on the NEET Physics previous year papers analysis

• Covers repeated concepts, important formulas, and key topics

• Focuses on NEET chapter-wise weightage and scoring areas

• Includes numerical, conceptual, and application-based questions

• Designed as per the patterns followed by the National Testing Agency

• Helps improve problem-solving skills, speed, and accuracy

Builds a strong foundation for NEET Physics 2026 preparation