Trigonometry For NEET: Concepts And Paper Analysis

Trigonometry For NEET: Concepts And Paper Analysis

Ramraj SainiUpdated on 13 Jun 2022, 03:22 PM IST

Trigonometry is the branch of Mathematics that deals with the study of the relationship between angles and sides and lengths of triangles. Trigonometry is not a part of the NEET syllabus, but the basic idea of Trigonometry is used to solve NEET Physics as well as some Chemistry questions. Therefore, it holds significant importance for NEET aspirants. This article includes trigonometric ratios and their value at different angles, basic identities, an analysis of five previous years questions and an explanation of trigonometric concepts using previous five years NEET Physics papers.

Trigonometry For NEET:  Concepts And Paper Analysis
Trigonometry For Solving NEET Questions(Image: Shutterstock)

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Angle And Trigonometric Ratios

Consider a right angled triangle ABC, The angle B is a right angle,

and the longest side AC is called the hypotenuse, and the other two

sides AB and BC respectively are called adjacent and opposite sides

corresponding to angle A .

Trigonometric ratios are defined as given below-

sinA = Opposite Side /Hypotenuse = BC/ AC

cosecA = Hypotenuse/ Opposite side = AC/BC

cosA = Adjacent Side /Hypotenuse = AB/ AC

secA = Hypotenuse/Adjacent side = AC/AB

tanA = Opposite Side/ Adjacent side = BC/ AB

cotA = Adjacent side Opposite side = AB/BC

tanA = sinA /cosA

cotA = cosA /sinA

Value Of Trigonometric Ratio At Different Angle

Degree

30°

45°

60°

90°

180°

270°

360°

Radian

0

π/6

π/4

π/3

π/2

π

3π/2

sin

0

1/2

1/√2

√3/2

1

0

-1

0

cos

1

√3/2

1/√2

1/2

0

-1

0

1

tan

0

1/√3

1

√3

0

0

cot

√3

1

1/√3

0

0

sec

1

2/√3

√2

2

-1

1

cosec

2

√2

2/√3

1

-1

Following visual representation includes the mnemonic phrase “ASTC” to remember trigonometric ratios where they are positive.

A: All positive

S: sinθ and cosecθ are positive

T: tanθ and cotθ are positive

C: cosθ and secθ are positive

Trigonometric Ratio In Different Quadrants

1654752674231

Trigonometric Ratios Of Allied Angle

Angle

90 - θ

(Ⅰ Quadrant)

90 + θ

(Ⅱ Quadrant)

180 - θ

(Ⅲ Quadrant)

180 + θ

(Ⅳ Quadrant)

sin

-sinθ

cosθ

cosθ

sinθ

-sinθ

cos

cosθ

sinθ

-sinθ

-cosθ

-cosθ

tan

-tanθ

cotθ

-cotθ

-tanθ

tanθ

Graph Of Trigonometric Function

1654752675843

Trigonometry Basic Identities And Rules

Complex formulas, identities, and rules of trigonometry are not relevant for NEET aspirants as these are neither directly asked nor indirectly used in any questions. Following the given identity and rules are important for NEET aspirants.

1654752672518

1654752671782

Apart from the above basic trigonometric relations, a few more formulas will be used while deriving equations. And understanding derivations is good for concept building and will make students aware of how a formula is obtained. Some of the trigonometric ideas used in Physics derivations are listed below

sine rule

If A, B, C are the angles of a triangle and a, b, and c are corresponding opposite sides then

a/sinA = b/sinB = c/sinC

1654752673097

cosine rule

c2 = a2 + b2 - 2ab cos C

b2 = a2 + c2 - 2ac cos B

a2 = b2 + c2 - 2bc cos A

Angle Sum Property

1654752676002

Analysis Of Previous Five Years NEET Paper

One of the important activities that help students to understand exam patterns is the analysis of the previous year's papers. Students realize important concepts and topics with their horizontal and vertical spread. After analyzing the last five years of NEET paper careers360 extracted important facts that are mentioned below. The smart study can be beneficial for NEET aspirants.

Number Of Questions In Which Trigonometry Is Used

Year

Number Of Questions

2021

3

2020

5

2019

4

2018

4

2017

2

There are an average of 2-5 questions being asked in the NEET exam every year which use trigonometry concepts.

NEET Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Previous Year's Questions To Understand The Concepts

Let's take some NEET previous year's questions or NEET PYQs to understand the application of trigonometry concepts. After analysing these questions, students can understand that mainly the value of trigonometry ratios at different angles are used to solve the problems.

1654752667356

Q-1 (NEET - 2021)

Find the value of the angle of emergency from the prism.

The Refractive index of the glass is 1654752671934.

  1. 1654752670140

  2. 1654752670554

  3. 1654752673239

  4. 1654752668587

Solution:

2nd Refracting Surface

1654752674978

\mu _{1}\sin 30^{o}=\mu _{2}\sin \theta

\sqrt{3}\times \frac{1}{2}=1\sin \theta

\theta =60^{o}

\theta =Angle\: of\: ehergence=60^{o}

Concept Used

The trigonometric ratio at different angles

sin30° = 1/2 and sin60° = √3/2.

Q-2 (NEET - 2020)

The phase difference between displacement and acceleration of a particle in a simple harmonic motion is:

  1. \mathrm{\pi \ rad}

  2. \mathrm{\frac{3\pi}{2} \ rad}

  3. \mathrm{\frac{\pi}{2} \ rad}

  4. zero

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Solution:

$$\begin{aligned} &\text { SHM is represented by }\ displacement= \mathrm{x}=\mathrm{A} \sin \omega \mathrm{t}\\ &\text { Then, the velocity and acceleration after differentiation will be }\\ &\mathbf{v}=\mathbf{A} \omega \cos \omega \mathbf{t}\\ &\mathrm{a}=-\mathrm{A} \omega^{2} \sin \omega \mathrm{t}=\mathrm{A} \omega^{2} \sin (\omega \mathrm{t}+\pi) \end{aligned}

So the phase difference between x & a is \mathrm{\pi \ rad}

Concept Used

We know the property sinθ = - sin(π+θ)

Q-3 (NEET - 2019)

The speed of a swimmer in still water is 20 m/s. The speed of river water is 10 m/s and is flowing due east. If he is standing on the south bank and wishes to cross the river along the shortest path, the angle at which he should make his strokes w.r.t north is given by:

  1. 30 west

  2. 0 \degree

  3. 60 \degree west

  4. 45 \degree west

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Solution:

1654752797333

Boat - River Problem

20 \sin \theta = 10 \Rightarrow \theta = 30 \degree west

Concept Used

The value of sin30° = 1/2

Q-4 (NEET - 2018)

A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and θ for the block to remain stationary on the wedge is

1654752668733

  1. 1655113753313

  2. a = \frac{g}{sin \theta }

  3. a = \frac{g}{cosec \theta }

  4. a = g tan \theta

Solution:

As we have learned, In Equilibrium of Concurrent Forces -

If all the forces working on a body are acting on the same point then they are said to be concurrent. Wherein



1654752676468

sum vec{F_{net}}= 0 or sum vec{F_{x}}= 0,sum vec F_{y}= 0, sum vec F_{z}= 0

Observing Free Body Diagram or FBD of the block

In given conditions, for Block to be a stationary

net force along the plane = 0 \Rightarrow mg\sin \theta =ma\cos \theta \Rightarrow a=g\tan \theta

Concept Used

Property: tanθ = sinθ/cosθ

Q-5 (NEET - 2017)

If θ1 and θ2 be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip θ is given by:

  1. cot2θ = cot2θ1 + cot2θ2

  2. tan2θ = tan2θ1 + tan2θ2

  3. cot2θ= cot2θ1 - cot2θ2

  4. tan2θ = tan2θ1 - tan2θ2

Solution:

If θ1 and θ2 are Apparent angles of dip Let α be the angle that one of the planes makes with the magnetic meridian.

tanθ = V/H where θ is the true angle of the dip

1654752674608

Concept Used

sin2θ + cos2θ = 1

cotθ = 1/tanθ

After analyzing the previous year's questions, students become aware that without mastering lengthy trigonometry formulas and concepts, having an understanding of basic concepts is sufficient for the NEET exam. You can easily learn it with the right strategy and consistent efforts.

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NEET

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