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Motion in a Straight Line NEET Questions are frequently asked in the NEET Physics exam. Practising NEET Previous Year Question paper (PYQs) helps aspirants to master this topic. This Motion in a Straight Line chapter is the foundation for concepts like distance, displacement, velocity, acceleration, and equations of motion. As per the NEET previous year paper analysis, around 2-3 questions are included each year from Motion in a Straight Line. Solving PYQs build confidece and shows the NEET Physics Previous Year Questions trend.
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NEET PYQ Chapterwise highlight Motion in a Straight Line as a scoring topic. The chapter tests conceptual clarity, the difference between distance and displacement, graph interpretation, and the speed of solving problems. Practice of Motion in Straight Line NEET previous year questions helps students identify the most repeated questions, difficulty levels, and NEET exam trends. It makes formulas easy to remember. PYQ practice explains why Motion in Straigth Line is important for NEET 2026 Physics.
A detailed analysis of Motion in a Straight Line NEET chapter-wise PYQ explains that the weightage is likely 2-3 questions (8-12 marks), consistent with previous years' questions (2015-2025).
High-Probability Topics:
Graphs: Velocity-time (slope = acceleration, area = displacement).
Equations of Motion: Applications in free fall, deceleration, or non-uniform acceleration.
Relative Velocity: Problems involving two objects moving in opposite/same direction.
Average Speed vs. Average Velocity: Conceptual distinctions.
Difficulty Level:
60% Medium (application-based), e.g., combining graphs with equations.
30% Easy (direct formula-based), e.g., calculating displacement.
10% Hard (twist in relative motion or free fall).
|
Year |
Total Questions |
Subtopic Breakdown |
Difficulty Level (E/M/H) |
|---|---|---|---|
|
2025 |
1 |
Acceleration (1) |
1E |
|
2024 |
3 |
Graphs (2), Free Fall (1) |
2E, 1M |
|
2023 |
2 |
Graphs (1), Relative Motion (1) |
1E, 1M |
|
2022 |
3 |
Equations of Motion (2), Free Fall (1) |
2M, 1H |
|
2021 |
2 |
Graphs (1), Average Speed (1) |
2E |
|
2020 |
1 |
Relative Velocity (1) |
1M |
|
2019 |
2 |
Equations of Motion (1), Acceleration (1) |
1E, 1H |
|
2018 |
3 |
Graphs (2), Free Fall (1) |
2M, 1E |
|
2017 |
2 |
Relative Motion (1), Equations of Motion (1) |
1M, 1H |
|
2016 |
1 |
Average Velocity (1) |
1E |
|
2015 |
2 |
Graphs (1), Free Fall (1) |
1E, 1M |
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Motion is Straight Line NEET Questions for the foundation of the NEET Physics syllabus. They are repeated almost every year. Practising NEET Previous Year Question Paper (PYQ) helps students identify the exact exam pattern and repeated concepts like displacement, velocity, and acceleration. It also shows how examiners frame tricky conceptual and numerical questions.
NEET Physics Previous Year Questions act as a roadmap for NEET 2026 Preparation. They highlight the important formula to remember and how the questions are structured. It is the basis of Unit Kinematics questions in the NEET 2026 Syllabus.
Aspirants are advised to go through some important physics formulas and derivations before practising from the motion in a straight line NEET question bank: Some important motion in a straight line formulas and derivations are:
1. Equations of Motion (constant acceleration):
Final velocity: $v = u + at$
Displacement: $s = ut + \frac{1}{2}at^2$
Third equation: $v^2 = u^2 + 2as$
2. Average speed (unequal time intervals):
$\text{Average speed} = \frac{\text{Total Distance}}{\text{Total Time}}$
3. Average speed (equal distances):
$\text{Average speed} = \frac{2 v_1 v_2}{v_1 + v_2}$
4. Relative velocity of A with respect to B:
$v_{A/B} = v_A - v_B$
5. Free fall velocity:
$v = u + gt$, where $g = +9.8\ \text{m/s}^2$ (if downward is positive)
6. Free fall height:
$h = ut + \frac{1}{2}gt^2$
7. Graphical relations:
Given below are NEET Physics Motion in a Straight Line previous year questions for analysis and practice. Once aspirants are done with studying the concepts, they can start practising from the previous year's NEET Physics questions on motion in a straight line.
Question 1:
Particle velocity is given by the relation $v = 2e^t + 3e^{2t}$. The acceleration at $t = 0\ \text{s}$ will be:
(1) $5\ \text{m/s}^2$
(2) $8\ \text{m/s}^2$
(3) $15\ \text{m/s}^2$
(4) $6\ \text{m/s}^2$
Correct Answer: (2) $8\ \text{m/s}^2$
Explanation:
Given:
$v = 2e^t + 3e^{2t}$
Acceleration:
$a = \frac{dv}{dt}$
$a = 2e^t + 6e^{2t}$
At $t = 0$:
$a = 2e^0 + 6e^0$
$a = 2 + 6$
$a = 8\ \text{m/s}^2$
Hence, the correct answer is option (2).
Question 2:
A particle is dropped from a tower. It travels $45\ \text{m}$ in the last second of its journey. Find the height of the tower. Take $g = 10\ \text{m/s}^2$.
(1) $200\ \text{m}$
(2) $125\ \text{m}$
(3) $370\ \text{m}$
(4) $120\ \text{m}$
Correct Answer: (2) $125\ \text{m}$
Explanation:
Displacement in $n^{\text{th}}$ second:
$S_n = u + \frac{a}{2} (2n - 1)$
Since $u = 0$,
$45 = \frac{10}{2} (2n - 1)$
$45 = 5(2n - 1)$
$45 = 10n - 5$
$50 = 10n$
$n = 5$
Height:
$h = \frac{1}{2} gt^2$
$h = \frac{1}{2} \times 10 \times 5^2$
$h = 125\ \text{m}$
Hence, the correct answer is option (2).
Question 3:
Velocity of aeroplane is $v = \sqrt{t} + \frac{2}{\sqrt{t}}$. Find acceleration.
(1) $\frac{1}{\sqrt{t}} - \frac{1}{t^{3/2}}$
(2) $\frac{4}{\sqrt{t}} + \frac{1}{2t}$
(3) $\frac{1}{\sqrt{t}} + \frac{1}{t^{3/2}}$
(4) $\frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$
Correct Answer: (4) $\frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$
Explanation:
$v = t^{1/2} + 2t^{-1/2}$
$a = \frac{dv}{dt}$
$a = \frac{1}{2} t^{-1/2} + 2 \left(-\frac{1}{2}\right) t^{-3/2}$
$a = \frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$
Hence, the correct answer is option (4).
Question 4:
Acceleration $A \propto \beta t^{n^2}$. Find how acceleration depends on $t$ when $n = e^2$.
(1) $t^{e^2}$
(2) $t^{e^4}$
(3) $t^{e^3}$
(4) $t^0$
Correct Answer: (2) $t^{e^4}$
Explanation:
$A \propto \beta t^{n^2}$
For $n = e^2$:
$A \propto \beta t^{(e^2)^2}$
$A \propto t^{e^4}$
Hence, the correct answer is option (2).
Question 5:
A particle moves such that displacement $s = t^3 - 6t^2 + 3t + 4$. Find velocity when acceleration is zero.
(1) $-9\ \text{m/s}$
(2) $-10\ \text{m/s}$
(3) $-6\ \text{m/s}$
(4) $-4\ \text{m/s}$
Correct Answer: (1) $-9\ \text{m/s}$
Explanation:
$v = \frac{ds}{dt} = 3t^2 - 12t + 3$
$a = \frac{dv}{dt} = 6t - 12$
For $a = 0$:
$6t - 12 = 0$
$t = 2$
$v = 3(2)^2 - 12 \times 2 + 3$
$v = 12 - 24 + 3$
$v = -9\ \text{m/s}$
Hence, the correct answer is option (1).
Speed $\neq$ Velocity: Speed is a scalar quantity with no direction. Velocity is a vector quantity where direction matters
Sign Errors in Free Fall: Using
Graph Confusion: Mixing up displacement time and velocity time graphs
Incorrect Average Speed: Assuming $\text{Average speed} = \frac{v_1 + v_2}{2}$ for unequal distances.
Relative Velocity Oversights: Forgetting to subtract velocities vectorially
Deceleration Misinterpretation: Deceleration is acceleration opposite to the velocity sign, depending on the coordinate system
Ignoring real-world factors: Assuming $g = 10\ \text{m/s}^2$ or neglecting air resistance. In NEET, $g = 9.8\ \text{m/s}^2$ is used if not mentioned.
Frequently Asked Questions (FAQs)
They show repeated exam patterns. Practising PYQ improves accuracy, speed, and confidence. Motion in a Straight Line NEET Questions are scoring topics in Physics.
Break problems into steps. Apply formulas for velocity, acceleration, and displacement. Practice NEET Physics PYQ daily to improve time management.
On Question asked by student community
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