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NEET Questions for Motion in a Straight Line are an essential component of NEET Physics preparation. The chapter lays down the basis for learning about the concepts of distance, displacement, velocity, acceleration, and equations of motion. Solving NEET PYQ Chapterwise questions on Motion in Straight Line will enable students to grasp the pattern in which these concepts are asked and solve numerical questions accurately.
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Practising NEET PYQ Chapterwise questions can be beneficial for aspirants in recognising frequently asked concepts, familiarising themselves with the question patterns, and enhancing their problem-solving skills. The concepts tested in this chapter include distinguishing between distance and displacement, interpretation of motion graphs, and use of equations of motion.
A detailed analysis of Motion in a Straight Line NEET chapter-wise PYQ explains that the weightage is likely 2-3 questions (8-12 marks), consistent with previous years' questions (2015-2026).
High-Probability Topics:
Graphs: Velocity-time (slope = acceleration, area = displacement).
Equations of Motion: Applications in free fall, deceleration, or non-uniform acceleration.
Relative Velocity: Problems involving two objects moving in opposite/same direction.
Average Speed vs. Average Velocity: Conceptual distinctions.
|
Year |
Total Questions |
Subtopic Breakdown |
Difficulty Level (E/M/H) |
|---|---|---|---|
| 2026 | 1 | Average speed | 1M |
|
2025 |
1 |
Acceleration (1) |
1E |
|
2024 |
3 |
Graphs (2), Free Fall (1) |
2E, 1M |
|
2023 |
2 |
Graphs (1), Relative Motion (1) |
1E, 1M |
|
2022 |
3 |
Equations of Motion (2), Free Fall (1) |
2M, 1H |
|
2021 |
2 |
Graphs (1), Average Speed (1) |
2E |
|
2020 |
1 |
Relative Velocity (1) |
1M |
|
2019 |
2 |
Equations of Motion (1), Acceleration (1) |
1E, 1H |
|
2018 |
3 |
Graphs (2), Free Fall (1) |
2M, 1E |
|
2017 |
2 |
Relative Motion (1), Equations of Motion (1) |
1M, 1H |
|
2016 |
1 |
Average Velocity (1) |
1E |
|
2015 |
2 |
Graphs (1), Free Fall (1) |
1E, 1M |
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Questions from Motion in a Straight Line NEET are significant from the point of view of the Kinematics topic of the NEET Physics Syllabus. Solving the Motion in a Straight Line NEET Previous Year Questions will assist students in getting familiar with the question pattern and concepts like displacement, velocity, and acceleration that are frequently asked in the exams. It will also help aspirants to understand how the questions are framed conceptually as well as numerically in the exams.
The NEET Physics Previous Year Questions will definitely help in NEET 2027 preparation in terms of understanding important formulas, the pattern of the questions, and solving problems quickly. Solving Kinematics Questions for NEET PYQ will be beneficial in strengthening the concepts of Motion in a Straight Line.
Aspirants are advised to go through some important physics formulas and derivations before practising from the motion in a straight line NEET question bank: Some important motion in a straight line formulas and derivations are:
1. Equations of Motion (constant acceleration):
Final velocity: $v = u + at$
Displacement: $s = ut + \frac{1}{2}at^2$
Third equation: $v^2 = u^2 + 2as$
2. Average speed (unequal time intervals):
$\text{Average speed} = \frac{\text{Total Distance}}{\text{Total Time}}$
3. Average speed (equal distances):
$\text{Average speed} = \frac{2 v_1 v_2}{v_1 + v_2}$
4. Relative velocity of A with respect to B:
$v_{A/B} = v_A - v_B$
5. Free fall velocity:
$v = u + gt$, where $g = +9.8\ \text{m/s}^2$ (if downward is positive)
6. Free fall height:
$h = ut + \frac{1}{2}gt^2$
7. Graphical relations:
Given below are NEET Physics Motion in a Straight Line previous year questions for analysis and practice. Once aspirants are done with studying the concepts, they can start practising from the previous year's NEET Physics questions on motion in a straight line.
Question 1:
Particle velocity is given by the relation $v = 2e^t + 3e^{2t}$. The acceleration at $t = 0\ \text{s}$ will be:
(1) $5\ \text{m/s}^2$
(2) $8\ \text{m/s}^2$
(3) $15\ \text{m/s}^2$
(4) $6\ \text{m/s}^2$
Correct Answer: (2) $8\ \text{m/s}^2$
Explanation:
Given:
$v = 2e^t + 3e^{2t}$
Acceleration:
$a = \frac{dv}{dt}$
$a = 2e^t + 6e^{2t}$
At $t = 0$:
$a = 2e^0 + 6e^0$
$a = 2 + 6$
$a = 8\ \text{m/s}^2$
Hence, the correct answer is option (2).
Question 2:
A particle is dropped from a tower. It travels $45\ \text{m}$ in the last second of its journey. Find the height of the tower. Take $g = 10\ \text{m/s}^2$.
(1) $200\ \text{m}$
(2) $125\ \text{m}$
(3) $370\ \text{m}$
(4) $120\ \text{m}$
Correct Answer: (2) $125\ \text{m}$
Explanation:
Displacement in $n^{\text{th}}$ second:
$S_n = u + \frac{a}{2} (2n - 1)$
Since $u = 0$,
$45 = \frac{10}{2} (2n - 1)$
$45 = 5(2n - 1)$
$45 = 10n - 5$
$50 = 10n$
$n = 5$
Height:
$h = \frac{1}{2} gt^2$
$h = \frac{1}{2} \times 10 \times 5^2$
$h = 125\ \text{m}$
Hence, the correct answer is option (2).
Question 3:
Velocity of aeroplane is $v = \sqrt{t} + \frac{2}{\sqrt{t}}$. Find acceleration.
(1) $\frac{1}{\sqrt{t}} - \frac{1}{t^{3/2}}$
(2) $\frac{4}{\sqrt{t}} + \frac{1}{2t}$
(3) $\frac{1}{\sqrt{t}} + \frac{1}{t^{3/2}}$
(4) $\frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$
Correct Answer: (4) $\frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$
Explanation:
$v = t^{1/2} + 2t^{-1/2}$
$a = \frac{dv}{dt}$
$a = \frac{1}{2} t^{-1/2} + 2 \left(-\frac{1}{2}\right) t^{-3/2}$
$a = \frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$
Hence, the correct answer is option (4).
Question 4:
Acceleration $A \propto \beta t^{n^2}$. Find how acceleration depends on $t$ when $n = e^2$.
(1) $t^{e^2}$
(2) $t^{e^4}$
(3) $t^{e^3}$
(4) $t^0$
Correct Answer: (2) $t^{e^4}$
Explanation:
$A \propto \beta t^{n^2}$
For $n = e^2$:
$A \propto \beta t^{(e^2)^2}$
$A \propto t^{e^4}$
Hence, the correct answer is option (2).
Question 5:
A particle moves such that displacement $s = t^3 - 6t^2 + 3t + 4$. Find velocity when acceleration is zero.
(1) $-9\ \text{m/s}$
(2) $-10\ \text{m/s}$
(3) $-6\ \text{m/s}$
(4) $-4\ \text{m/s}$
Correct Answer: (1) $-9\ \text{m/s}$
Explanation:
$v = \frac{ds}{dt} = 3t^2 - 12t + 3$
$a = \frac{dv}{dt} = 6t - 12$
For $a = 0$:
$6t - 12 = 0$
$t = 2$
$v = 3(2)^2 - 12 \times 2 + 3$
$v = 12 - 24 + 3$
$v = -9\ \text{m/s}$
Hence, the correct answer is option (1).
Speed $\neq$ Velocity: Speed is a scalar quantity with no direction. Velocity is a vector quantity where direction matters
Sign Errors in Free Fall: Using
Graph Confusion: Mixing up displacement time and velocity time graphs
Incorrect Average Speed: Assuming $\text{Average speed} = \frac{v_1 + v_2}{2}$ for unequal distances.
Relative Velocity Oversights: Forgetting to subtract velocities vectorially
Deceleration Misinterpretation: Deceleration is acceleration opposite to the velocity sign, depending on the coordinate system
Ignoring real-world factors: Assuming $g = 10\ \text{m/s}^2$ or neglecting air resistance. In NEET, $g = 9.8\ \text{m/s}^2$ is used if not mentioned.
Frequently Asked Questions (FAQs)
They show repeated exam patterns. Practising PYQ improves accuracy, speed, and confidence. Motion in a Straight Line NEET Questions are scoring topics in Physics.
Break problems into steps. Apply formulas for velocity, acceleration, and displacement. Practice NEET Physics PYQ daily to improve time management.
On Question asked by student community
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