Motion in Straight Line NEET Questions - NEET Previous Year Questions Papers (PYQ)

Motion in a Straight Line NEET PYQ Analysis (2015-2026)

A detailed analysis of Motion in a Straight Line NEET chapter-wise PYQ explains that the weightage is likely 2-3 questions (8-12 marks), consistent with previous years' questions (2015-2026).

High-Probability Topics:

• Graphs: Velocity-time (slope = acceleration, area = displacement).

• Equations of Motion: Applications in free fall, deceleration, or non-uniform acceleration.

• Relative Velocity: Problems involving two objects moving in opposite/same direction.

• Average Speed vs. Average Velocity: Conceptual distinctions.

As can be seen from the above data, there can be a wide variation in the number of questions asked. Thus, it would be appropriate for candidates to apply the technique of PYQ analysis to find the most important topics, and not take it for granted that there will always be the same number of questions asked in NEET 2027.

Why Motion in a Straight Line NEET Previous Year Questions Matter

Questions from Motion in a Straight Line NEET are significant from the point of view of the Kinematics topic of the NEET Physics Syllabus. Solving the Motion in a Straight Line NEET Previous Year Questions will assist students in getting familiar with the question pattern and concepts like displacement, velocity, and acceleration that are frequently asked in the exams. It will also help aspirants to understand how the questions are framed conceptually as well as numerically in the exams.

The NEET Physics Previous Year Questions will definitely help in NEET 2027 preparation in terms of understanding important formulas, the pattern of the questions, and solving problems quickly. Solving Kinematics Questions for NEET PYQ will be beneficial in strengthening the concepts of Motion in a Straight Line.

Important Topics in Motion in a Straight Line for NEET

Considering the existing syllabus and trends in previous years’ questions, one should focus on:

• Distance and displacement
• Speed and velocity
• Average speed and average velocity
• Instantaneous velocity and acceleration
• Uniform and non-uniform motion
• Equations for uniformly accelerated motion
• Position-time graph and velocity-time graph
• Free fall motion
• Relative velocity
• Motion graphs interpretation

The official NEET syllabus for kinematics includes: Position-time graph, speed and velocity, average speed, instantaneous velocity, uniformly accelerated motion, velocity-time graph, and relative velocity.

Motion in a Straight Line PYQ for NEET 2027: Important Formulas and Derivations

Aspirants are advised to go through some important physics formulas and derivations before practising from the motion in a straight line NEET question bank: Some important motion in a straight line formulas and derivations are:

1. Equations of Motion (constant acceleration):

Final velocity: $v = u + at$

Displacement: $s = ut + \frac{1}{2}at^2$

Third equation: $v^2 = u^2 + 2as$

2. Average speed (unequal time intervals):

$\text{Average speed} = \frac{\text{Total Distance}}{\text{Total Time}}$

3. Average speed (equal distances):

$\text{Average speed} = \frac{2 v_1 v_2}{v_1 + v_2}$

4. Relative velocity of A with respect to B:

$v_{A/B} = v_A - v_B$

5. Free fall velocity:

$v = u + gt$, where $g = +9.8\ \text{m/s}^2$ (if downward is positive)

6. Free fall height:

$h = ut + \frac{1}{2}gt^2$

7. Graphical relations:

• Slope of $s-t$ graph $=$ instantaneous velocity
• Slope of $v-t$ graph $=$ acceleration
• Area under $v-t$ graph $=$ displacement

Motion in a Straight Line NEET Important Questions

Given below are NEET Physics Motion in a Straight Line previous year questions for analysis and practice. Once aspirants are done with studying the concepts, they can start practising from the previous year's NEET Physics questions on motion in a straight line.

Question 1:

Particle velocity is given by the relation $v = 2e^t + 3e^{2t}$. The acceleration at $t = 0\ \text{s}$ will be:

(1) $5\ \text{m/s}^2$
(2) $8\ \text{m/s}^2$
(3) $15\ \text{m/s}^2$
(4) $6\ \text{m/s}^2$

Correct Answer: (2) $8\ \text{m/s}^2$

Explanation:

Given:
$v = 2e^t + 3e^{2t}$

Acceleration:
$a = \frac{dv}{dt}$

$a = 2e^t + 6e^{2t}$

At $t = 0$:

$a = 2e^0 + 6e^0$
$a = 2 + 6$
$a = 8\ \text{m/s}^2$

Hence, the correct answer is option (2).

Question 2:

A particle is dropped from a tower. It travels $45\ \text{m}$ in the last second of its journey. Find the height of the tower. Take $g = 10\ \text{m/s}^2$.

(1) $200\ \text{m}$
(2) $125\ \text{m}$
(3) $370\ \text{m}$
(4) $120\ \text{m}$

Correct Answer: (2) $125\ \text{m}$

Explanation:

Displacement in $n^{\text{th}}$ second:
$S_n = u + \frac{a}{2} (2n - 1)$

Since $u = 0$,
$45 = \frac{10}{2} (2n - 1)$

$45 = 5(2n - 1)$
$45 = 10n - 5$
$50 = 10n$
$n = 5$

Height:
$h = \frac{1}{2} gt^2$

$h = \frac{1}{2} \times 10 \times 5^2$
$h = 125\ \text{m}$

Hence, the correct answer is option (2).
Question 3:

Velocity of aeroplane is $v = \sqrt{t} + \frac{2}{\sqrt{t}}$. Find acceleration.

(1) $\frac{1}{\sqrt{t}} - \frac{1}{t^{3/2}}$
(2) $\frac{4}{\sqrt{t}} + \frac{1}{2t}$
(3) $\frac{1}{\sqrt{t}} + \frac{1}{t^{3/2}}$
(4) $\frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$

Correct Answer: (4) $\frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$

Explanation:

$v = t^{1/2} + 2t^{-1/2}$

$a = \frac{dv}{dt}$

$a = \frac{1}{2} t^{-1/2} + 2 \left(-\frac{1}{2}\right) t^{-3/2}$

$a = \frac{1}{2\sqrt{t}} - \frac{1}{t^{3/2}}$

Hence, the correct answer is option (4).
Question 4:

Acceleration $A \propto \beta t^{n^2}$. Find how acceleration depends on $t$ when $n = e^2$.

(1) $t^{e^2}$
(2) $t^{e^4}$
(3) $t^{e^3}$
(4) $t^0$

Correct Answer: (2) $t^{e^4}$

Explanation:

$A \propto \beta t^{n^2}$

For $n = e^2$:

$A \propto \beta t^{(e^2)^2}$
$A \propto t^{e^4}$

Hence, the correct answer is option (2).
Question 5:

A particle moves such that displacement $s = t^3 - 6t^2 + 3t + 4$. Find velocity when acceleration is zero.

(1) $-9\ \text{m/s}$
(2) $-10\ \text{m/s}$
(3) $-6\ \text{m/s}$
(4) $-4\ \text{m/s}$

Correct Answer: (1) $-9\ \text{m/s}$

Explanation:

$v = \frac{ds}{dt} = 3t^2 - 12t + 3$

$a = \frac{dv}{dt} = 6t - 12$

For $a = 0$:

$6t - 12 = 0$
$t = 2$

$v = 3(2)^2 - 12 \times 2 + 3$
$v = 12 - 24 + 3$
$v = -9\ \text{m/s}$

Hence, the correct answer is option (1).

Solving Motion in a Straight Line NEET Chapter-wise PYQ: Common Mistakes

1. Speed $\neq$ Velocity: Speed is a scalar quantity with no direction. Velocity is a vector quantity where direction matters

2. Sign Errors in Free Fall: Using $g=+9.8{\text{m/s}}^2$ even when upward is chosen as positive

3. Graph Confusion: Mixing up displacement time and velocity time graphs

4. Incorrect Average Speed: Assuming $\text{Average speed} = \frac{v_1 + v_2}{2}$ for unequal distances.

5. Relative Velocity Oversights: Forgetting to subtract velocities vectorially
   ${\mathrm{\$v\_\{\backslash text\{rain,\; man\}\}\; =\; v\_\{\backslash text\{rain\}\}\; -\; v\_\{\backslash text\{man\}\}\$}}_{}$

6. Deceleration Misinterpretation: Deceleration is acceleration opposite to the velocity sign, depending on the coordinate system

7. Ignoring real-world factors: Assuming $g = 10\ \text{m/s}^2$ or neglecting air resistance. In NEET, $g = 9.8\ \text{m/s}^2$ is used if not mentioned.