Motion in Straight Line NEET Questions - NEET Previous Year Questions Papers (PYQ)

Edited By Irshad Anwar | Updated on Mar 25, 2025 10:11 AM IST | #NEET

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Motion in a Straight Line NEET PYQ analysis: Comprising of more than 20 lakh candidates competing for restricted seats in medical institutions, the National Eligibility Cum Entrance Test (NEET) is India's main medical entrance examination. There are 45 questions (180 marks) for the NEET physics section.

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This Story also Contains

Motion in a Straight Line NEET PYQ Analysis (2024-2015)
Important Formulas and Derivations
Motion in Straight NEET Previous Year Questions
Common Mistakes and Misconceptions

Motion in Straight Line NEET Questions - NEET Previous Year Questions Papers (PYQ)

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Among the several chapters, Motion on a Straight Line is a fundamental chapter in Kinematics, necessary for understanding motion-related problems. Since it lays the foundation for higher topics like projectile motion and circular motion, the chapter Motion in a Straight Line is important in the Kinematics unit in NEET Physics. With an annual weightage of 2-3 questions, learning this chapter is essential for achieving 8–12 marks, considerably affecting total results. For NEET aspirants, a strong grasp of this chapter is non-negotiable—it bridges basic mechanics and higher-order concepts, making it a strategic stepping stone in exam preparation.

Motion in a Straight Line NEET PYQ Analysis (2024-2015)

Weightage: Likely 2-3 questions (8–12 marks), consistent with previous years' questions (2024-2015).

High-Probability Topics:

Graphs: Velocity-time (slope = acceleration, area = displacement).
Equations of Motion: Applications in free fall, deceleration, or non-uniform acceleration.
Relative Velocity: Problems involving two objects moving in opposite/same directions.
Average Speed vs. Average Velocity: Conceptual distinctions.

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Difficulty Level:

60% Medium (application-based), e.g., combining graphs with equations.
30% Easy (direct formula-based), e.g., calculating displacement.
10% Hard (twist in relative motion or free fall).

Most Scoring concepts for NEET

This ebook serves as a valuable study guide for NEET exams, specifically designed to assist students in light of recent changes and the removal of certain topics from the NEET exam.

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Year	Total Questions	Subtopic Breakdown	Difficulty Level (E/M/H)
2024	3	Graphs (2), Free Fall (1)	2E, 1M
2023	2	Graphs (1), Relative Motion (1)	1E, 1M
2022	3	Equations of Motion (2), Free Fall (1)	2M, 1H
2021	2	Graphs (1), Average Speed (1)	2E
2020	1	Relative Velocity (1)	1M
2019	2	Equations of Motion (1), Acceleration (1)	1E, 1H
2018	3	Graphs (2), Free Fall (1)	2M, 1E
2017	2	Relative Motion (1), Equations of Motion (1)	1M, 1H
2016	1	Average Velocity (1)	1E
2015	2	Graphs (1), Free Fall (1)	1E, 1M

Also Read:

Important Formulas and Derivations

Some important formulas and derivations are:

Equations of Motion (constant acceleration):

Final velocity: v=u+at
Displacement: s=ut+(1/2)at2
Velocity-displacement relation: v2=u2+2as
Derivation: These are derived by integrating acceleration or using velocity-time graphs.

Average Speed: For unequal time intervals: Total Distance / Total Time.

For equal distances: (2v1v2)/(v1+v2).

Relative Velocity:

Velocity of A relative to B: vA−vB (vector subtraction).

Free Fall:

Velocity: v=u+gt (use g=+9.8 m/s2 if downward is positive).
Height: h=ut+(1/2)gt2

Graphical Relations:

Slope of displacement-time graph = Instantaneous velocity.
Slope of velocity-time graph = Acceleration.
Area under velocity-time graph = Displacement.

Motion in Straight NEET Previous Year Questions

Question 1: A man is standing $40 m$ behind the bus. The bus starts with $1 \mathrm{~m} / \mathrm{sec}^2$ constant acceleration, and at the same instant, the man starts moving at constant speed $9 \mathrm{~m} / \mathrm{s}$. The time taken by a man to catch the bus?

8 sec
6 sec
8 sec or 10 sec
None

Solution: 1742148102377

let after time ' t ' man will catch the bus.
for bus -

\[\begin{aligned} & x = x_0 + ut + \frac{1}{2} a t^2, \quad x = 40 + 0(t) + \frac{1}{2} (1) t^2 \\ & x = 40 + \frac{t^2}{2} \quad \text{...(1)} \\ & \text{For man: } x = 9t \quad \text{...(2)}\end{aligned}\]

From equations (1) and (2),

\[\begin{aligned} & 40 + \frac{t^2}{2} = 9t \\ & 80 + t^2 = 18t \\ & t^2 - 18t + 80= 0\end{aligned}\]

Now,

\[\begin{aligned} & t^2 - (10+8)t + 80 = 0 \\ & t^2 - 10t - 8t + 80 = 0 \\ & t(t-10) -8(t-10) = 0 \\ & (t-10)(t-8) = 0 \\ & t - 10 = 0, \quad t - 8 = 0 \\ & t = 10 \text{ sec}, \quad t = 8 \text{ sec}\end{aligned}\]

Hence, the answer is option (3).

Question 2: A particle is dropped from a tower. It's found that it travels 45 m in the last second of its journey. Find out the height of the tower.

$\left(\right.$ take $\left.g=10 \mathrm{~m} / \mathrm{s}^2\right)$

200 m
125 m
370 m
120 m

Solution: Let the total time of the journey be n seconds. using,

$$\begin{aligned}S_n=u+\frac{a}{2}(2 n-1) \Rightarrow 45 & =0+\frac{10}{2}(2 n-1)\\45 & =5(2 n-1) \\45 & =10 n-5 \\50 & =10 n \\n & =5\end{aligned}$$

Height of the tower

$$\begin{aligned}& h=u t+\frac{1}{2} g t^2 \\& h=0+\frac{1}{2} \times 10 \times 25\\& h=5 \times 25 \\& h=125 \mathrm{~m}\end{aligned}$$
Hence, the answer is option (2).

Question 3: An aeroplane is moving with velocity $\mathrm{ \left(\sqrt{t}+\frac{2}{\sqrt{t}}\right)}$ , where t is time. When the aeroplane is at its maximum height, the aeroplane will become stable. After some time, return to the runway with the same velocity. What will be the acceleration at that particular time?

$\mathrm{\frac{1}{\sqrt{t}}-\frac{1}{t^{3 / 2}}}$
$\mathrm{\frac{4}{\sqrt{t}}+\frac{1}{2 \sqrt{t}}}$
$\mathrm{\frac{1}{\sqrt{t}}+\frac{1}{t^{3 / 2}}}$
$\mathrm{\frac{1}{2 \sqrt{t}}-\frac{1}{t^{3 / 2}}}$

Solution: Velocity of the aeroplane $\mathrm{=\sqrt{t}+\frac{2}{\sqrt{t}}}$

Acceleration of the aeroplane:

$\mathrm{a=\frac{d}{d t}\left[\sqrt{t}+\frac{2}{\sqrt{t}}\right]}$

$\mathrm{ \begin{aligned} a & =\frac{d}{d t}\left[t^{1 / 2}+2 t^{-1 / 2}\right] \\ a & =\frac{1}{2} t^{-1 / 2}+2\left(-\frac{1}{2}\right) t^{-3 / 2} \\ \frac{d v}{d t}=a \Rightarrow & \frac{1}{2 \sqrt{t}}-\frac{1}{t^{3 / 2}} \end{aligned} }$

Hence, the answer is option (4).

Question 4: A boy moving with acceleration $\mathrm{ A\, \, \alpha \, \, \beta t^{n^2}}$ , acceleration is proportional to _______ when $\mathrm{ n}$ becomes $\mathrm{e^2}$ :

$\mathrm{(t)^{e^2}}$
$\mathrm{(t)^{e^4}}$
$\mathrm{(t)^{e^3}}$
$\mathrm{(t)^{e^0}}$

Solution: Acceleration is given by the statement -

$\mathrm{ \text { Acceleration } \frac{d V}{d t}=A \alpha \beta t^{n^2}-(1) }$

from question, n becomes $\mathrm{e^2}$ , put in (1) -

$\mathrm{ \begin{aligned} & \frac{d v}{d t}=\frac{d^2 s}{d t^2} \Rightarrow a=A \alpha \beta t^{\left(e^2\right)^2} =\frac{A \alpha \beta t^{e^4}}{1} \\ & \frac{d v}{d t}\propto t^{e^4} \text { Ans. } \\ & \end{aligned} }$

Hence, the answer is option (2).

Question 5: A Particle is released from rest at point O, as shown in the figure. The acceleration of the particle at point B will be ____

1742148102878

$1024 \alpha$
$1024 \alpha^2$
$10240 \alpha$
$5012 \alpha$

Solution:

Velocity at point $0=0 \mathrm{~m} / \mathrm{s}$.
Velocity at point $\mathrm{A}=\alpha \mathrm{t}^4$
Velocity at point $\mathrm{B}=\alpha \mathrm{t}^{10}$
Now,
Acceleration at point $(B)=\frac{d}{d t}$ (velocity at point $B$ )

$\begin{aligned}& =\frac{d}{d t} \alpha t^{10} \\& =10 \alpha t^9\end{aligned}$
Acceleration at point $(B)=10 \alpha t^9$
but at point B t $=2 \mathrm{sec}$, acceleration will become-

$\begin{aligned}\text { Acceleration (a) } & =10 \alpha(2)^9 \\& =10 \alpha \times 1024 \\& =10240 \alpha\end{aligned}$

Hence, the answer is option (3).

Question 6: A particle moving with acceleration $\mathrm{a=\left(2 t^2+t\right) \cdot \mathrm{m} / \mathrm{s}^2}$ , the velocity between $\mathrm{t=1 \mathrm{sec}}$ to $\mathrm{t=2\, \mathrm{sec}}$ will be

$\mathrm{40 \mathrm{~m} / \mathrm{s}}$
$\mathrm{30 / 6 \mathrm{~m} / \mathrm{s}}$
$\mathrm{37 / 6 \mathrm{~m} / \mathrm{s}}$
$\mathrm{30 / 7 \mathrm{~m} / \mathrm{s} \text {. }}$

Solution: $\mathrm{\text { Acceleration } a=2 t^2+t\, \, \, \, -\text { (1) }}$

To find velocity, we have to integrate it -

$\mathrm{\begin{aligned} & v=\int_{\perp}^{2 s} a d t=\int_1^2\left(2 t^2+t\right) d t \\ & v=\left[\frac{2 t^3}{3}+\frac{t^2}{2}\right]_1^2 \end{aligned}}$

$\mathrm{v=\left[\left(\frac{16}{3}+\frac{4}{2}\right)-\left(\frac{2}{3}+\frac{1}{2}\right)\right]}$

$\mathrm{v=\left[\frac{16}{3}+2-\frac{2}{3}-\frac{1}{2}\right]=\frac{16-2}{3}+\frac{3}{2}}$

$\mathrm{\begin{aligned} & v=\frac{14}{3}+\frac{3}{2}=\frac{28+9}{6}=\frac{37}{6} \\ & v=\frac{37}{6} \mathrm{~m} / \mathrm{s} . \text { } \end{aligned}}$

Hence, the answer is option (3).

Question 7: Particle velocity is given by the relation $\mathrm{v=2 e^t+3 e^{2 t}}$ , the Acceleration at $\mathrm{t=0 \, \mathrm{sec} }$ will be :

$\mathrm{5 \mathrm{~m} / \mathrm{s}^2}$
$\mathrm{8 \mathrm{~m} / \mathrm{s}^2}$
$\mathrm{15 \mathrm{~m} / \mathrm{s}^2}$
$\mathrm{6 \mathrm{~m} / \mathrm{s}^2}$

Solution: Given:

$\mathrm{v=2 e^t+3 e^{2 t}}$

$\mathrm{\text { Acceleration } a=\frac{d v}{d t}=\frac{d}{d t}\left[2 e^t+3 e^{2 t}\right]}$

$\mathrm{a=2 e^t+6 e^{2 t}}$

Acceleration at $\mathrm{t=0 \, \mathrm{sec} }$ will be -

$\mathrm{a=2 e^0+6 e^{2 \times 0} \quad\left[\because e^0=1\right]}$

$\mathrm{\begin{aligned} & a=2 e^0+6 e^0 \\ & a=2 \times 1+6 \times 1 \\ & a=8 \mathrm{~m} / \mathrm{s}^2 \text { } \end{aligned}}$

Hence, the answer is option (2).

Question 8: A particle moves along a straight line such that its displacement at any time t is given by $\mathrm{s=\left(t^3-6 t^2+3 t+4\right) \mathrm{m}.}$

The velocity when the acceleration is zero

$\mathrm{-9 \mathrm{~m} / \mathrm{s}$
$-10 \ m/s$
$\mathrm{-6 \mathrm{~m} / \mathrm{s}}$
$\mathrm{-4 \mathrm{~m} / \mathrm{s}}$

Solution: Given $\mathrm{s=t^3-6 t^2+3 t+4}$

$\mathrm{\text { velocity } v=\frac{d s}{d t}=\frac{d}{d t}\left[t^3-6 t^2+3 t+4\right]}$

$\mathrm{=3 t^2-12 t+3\, \, \, \, \, \, -(1)}$

$\mathrm{\text { Acceleration } a=\frac{d v}{d t}=\frac{d}{d t}\left[3 t^2-12 t+3\right]}$

$\mathrm{a=6 t-12 \text {\, \, \, \, - (2) }}$

But acceleration is zero-
$\mathrm{ a=\frac{d v}{d t}=0 }$

$\mathrm{from (2) -}$

$\mathrm{\begin{array}{r} 0=6 t-12 \\ t=2 \mathrm{sec} \end{array}}$

Now,

put $\mathrm{ t=2\, \mathrm{sec} }$ in equation - (1) we get velocity

$\mathrm{ \begin{aligned} & v=3(2)^2+12 \times 2+3 \\ & v=12-24+3 \\ & v=-12+3=-9 \mathrm{~m} / \mathrm{s} \text { Ans. } \end{aligned}}$

Hence, the answer is option (1).

Question 9: A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backwards, and so on. Each step is 1 m long and requires 1 s. The time when he will fall into the pit 13 m away from him is:-

13 s
37 s
40 s
42 s

Solution: The time taken to move net 2 steps ( 5 steps forward and 3 steps backward) is 8 sec, and so far, 8 steps he takes 32 s. In the last 5 steps, he will take 5 seconds and fall into the pit.
Therefore, the Total time taken is 32 sec + 5 sec = 37 sec

Hence, the answer is option (2).

Common Mistakes and Misconceptions

Speed ≠ Velocity: Speed is scalar (no direction); velocity is vector (direction matters).
Sign Errors in Free Fall: Using g=+9.8 m/s2 even when upward is chosen as positive.
Graph Confusion: Mixing up displacement-time and velocity-time graphs.
Incorrect Average Speed: Assuming Avg. speed = (v1+v2)/2 for unequal distances.
Relative Velocity Oversights: Forgetting to subtract velocities vectorially (e.g., vrain, man=vrain−vman ).
Deceleration Misinterpretation: Deceleration is acceleration opposite to velocity (sign depends on coordinate system).
Ignoring Real-World Factors: Assuming g=10 m/s2 or neglecting air resistance (NEET uses 9.8 m/s2 if not mentioned in the question).

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Questions related to NEET

Have a question related to NEET ?

pgimsr Rohtak for bpt required neet??

No, NEET is not required for admission to the BPT (Bachelor of Physiotherapy) course at PGIMS Rohtak.

Admission Process:

Admission is through a Common Entrance Test (CET) conducted by the university itself.

10+2 with Physics, Chemistry, Biology, and English is mandatory.

Minimum marks: 45% (General) and 40% (SC/ST/OBC).

Other Details:

Course Duration: 4 years

Seats Available: Around 30

Fees: Approximately 12,000–15,000 per year

Read Complete Answer

harsh singh 26 April,2025

I did really bad in my class 12 boards due to some personal issues. Can i still persue mbbs after neet?

The eligibility varies based on the category. General category candidates need a minimum of 50%, while SC/ST/OBC/Reserved-PWD candidates require a minimum of 40%. General-PWD candidates need at least 45%. .

If your class 12th percentage meets the minimum eligibility criteria required for your category, then you are eligible for NEET and can pursue MBBS if you clear the cutoff for the exam.

Read Complete Answer

lisa 26 April,2025

How minimum marks required in neet to get bsc nursing and bpt in igims

Hi aspirant,

To pursue a B.Sc. in Nursing at IGIMS, you do not need a NEET score; instead, you must prepare for the CET. For the BPT program, it is recommended to score above 400 marks to stay competitive. The NEET UG exam is proposed to be conducted by May 4, 2025.

Read Complete Answer

Vedant Rathi 26 April,2025

Can i wear skirt in neet examination

As per NEET 2024 Dress Code (for females):

Light-colored clothes with half sleeves are allowed.

Skirts are allowed, but only knee-length or below.

Avoid metallic elements, big buttons, brooches, etc.

No high heels or fancy footwear — wear slippers or low-heel sandals.

Read Complete Answer

harsh singh 25 April,2025

Neet cutoff for bpt course 2025

The admission process and cutoff scores for the Bachelor of Physiotherapy (BPT) course in 2025 are distinct from those of MBBS and BDS, for which NEET is the primary entrance exam. While some BPT colleges might consider NEET scores, it is generally not the mandatory entrance examination for all BPT admissions across India.

The admission criteria for BPT courses typically involve your marks in the Class 12th board examinations, with Physics, Chemistry, and Biology as the main subjects. Many colleges admit students based on merit, considering the aggregate marks obtained in these subjects. A minimum aggregate score of 50% in PCB is a common eligibility criterion, although this can vary slightly between institutions. Some colleges might offer a relaxation of 5% for reserved categories like OBC, SC, and ST.

However, it's important to note that some universities and states do conduct their own entrance examinations for BPT admissions. Additionally, a few private colleges might consider NEET scores as part of their admission process, although it's usually not the sole criterion. State-level entrance exams might also be relevant for admissions to BPT colleges within a particular state. For example, in Maharashtra, the Maharashtra Common Entrance Test (MHT CET) has been used for BPT admissions.

Therefore, to ascertain the specific cutoff for a BPT course in 2025, you need to identify the particular colleges you are interested in. Then, you should check their individual admission criteria, which will be available on their official websites or admission brochures. These sources will provide the most accurate information regarding whether they consider NEET scores, conduct their own entrance tests, or admit students based solely on their Class 12th marks and the required cutoff percentages. Keep an eye on the admission notifications of your preferred colleges for the most up-to-date details.

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SUKRITI GUPTA 25 April,2025

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A career in pathology in India is filled with several responsibilities as it is a medical branch and affects human lives. The demand for pathologists has been increasing over the past few years as people are getting more aware of different diseases. Not only that, but an increase in population and lifestyle changes have also contributed to the increase in a pathologist’s demand. The pathology careers provide an extremely huge number of opportunities and if you want to be a part of the medical field you can consider being a pathologist. If you want to know more about a career in pathology in India then continue reading this article.

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Veterinary Doctor

A veterinary doctor is a professional, working in animal healthcare. He or she conducts medical examinations, diagnoses, and treats various illnesses of animals. Animals have distinct internal organs and functions, requiring specialised attention from a veterinary doctor. A doctor who treats humans cannot offer the same level of care to animals due to these variations. Therefore, a veterinary doctor plays a critical role in animal welfare.

Veterinary professionals prevent illness by providing vaccines and offering advice on animal nutrition and overall health. Their knowledge extends beyond household animals and includes livestock, wildlife, and exotic animals. Individuals who love animals and want to treat their illnesses, injuries, and diseases must opt for a career as a veterinary doctor.

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Speech Therapist

Speech therapists are essential medical professionals addressing speech disorders. Whether it's delayed speech in children or difficulties in pronunciation, these experts play a crucial role. This article explores how to become a speech therapist in India, covering courses, colleges, and the responsibilities of this impactful profession.

4 Jobs Available

Gynaecologist

Gynaecology can be defined as the study of the female body. The job outlook for gynaecology is excellent since there is evergreen demand for one because of their responsibility of dealing with not only women’s health but also fertility and pregnancy issues. Although most women prefer to have a women obstetrician gynaecologist as their doctor, men also explore a career as a gynaecologist and there are ample amounts of male doctors in the field who are gynaecologists and aid women during delivery and childbirth.

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Audiologist

The audiologist career involves audiology professionals who are responsible to treat hearing loss and proactively preventing the relevant damage. Individuals who opt for a career as an audiologist use various testing strategies with the aim to determine if someone has a normal sensitivity to sounds or not. After the identification of hearing loss, a hearing doctor is required to determine which sections of the hearing are affected, to what extent they are affected, and where the wound causing the hearing loss is found. As soon as the hearing loss is identified, the patients are provided with recommendations for interventions and rehabilitation such as hearing aids, cochlear implants, and appropriate medical referrals. While audiology is a branch of science that studies and researches hearing, balance, and related disorders.

3 Jobs Available

Oncologist

An oncologist is a specialised doctor responsible for providing medical care to patients diagnosed with cancer. He or she uses several therapies to control the cancer and its effect on the human body such as chemotherapy, immunotherapy, radiation therapy and biopsy. An oncologist designs a treatment plan based on a pathology report after diagnosing the type of cancer and where it is spreading inside the body.

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Anatomist

Are you searching for an ‘Anatomist job description’? An Anatomist is a research professional who applies the laws of biological science to determine the ability of bodies of various living organisms including animals and humans to regenerate the damaged or destroyed organs. If you want to know what does an anatomist do, then read the entire article, where we will answer all your questions.

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Narcotics Officer

A Narcotics Officer is an officer employed by the state to investigate the usage of drugs and their trafficking. A narcotics officer conducts undercover operations, investigates suspected drug dealers, executes raids and other appropriate actions for arresting these traffickers to reduce the circulation of drugs in the country.

A narcotics officer works in collaboration with other government agencies to stop drug trafficking at borders. He or she engages with various NGOs and public organisations to teach people about the dangerous effects of drug usage. A narcotics officer plays an important role in reducing the illegal activities of drug dealers and the circulation of drugs in the nation.

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Research Associate

If we talk about a career as a research associate, it all comes down to one thing - curiosity towards nature and the passion to find answers. A career as a research associate is full of thrill and excitement. However, a research associate also faces a lot of challenges and failures while working on a project. A job of a research associate includes a spectrum of Science as a subject in detail.

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Drug Inspector

A career as a Drug Inspector is regarded as one of the most diverse in the field of healthcare and pharmacy. Candidates must undergo a screening process administered by the UPSC and or SPSCs in order to become drug inspectors. Those who manage it through the selection process will have a rewarding career with a high salary.

2 Jobs Available

Biotechnologist

A Biotechnologist is a professional who possesses strong knowledge and techniques that are utilised in creating and developing innovative products that improve the quality of human life standards. A biochemist uses biological organisms to create and improve goods and procedures for agriculture, medicine, and sustainability. He or she researches the genetic, chemical, and physical characteristics of cells, tissues, and organisms to determine how they can be used industrially.

2 Jobs Available

R&D Personnel

A career as R&D Personnel requires researching, planning, and implementing new programs and protocols into their organization and overseeing new products’ development. He or she uses his or her creative abilities to improve the existing products as per the requirements of the target market.

2 Jobs Available